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4 years ago

What is a sharp ridge separating two cirques

1 answer:

7 0

Arete is a sharp ridge separating two cirques or glacial vallies found in mountain regions. It is French for fishbone or the backbone of a fish, spine

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Provide two ways that objects can become charged

kap26 [50]

Answer:

friction, conduction and induction

Explanation:

Had it in class I had it correct hope this helps.

8 0

3 years ago

A student does 25 J of work on the handle of a pencil sharpener. If the pencil sharpener does 20 J of work on the pencil, what i

allsm [11]

Answer:

80%

Explanation:

Efficiency of machine = work output/work input ×100 %

From question, work output = 20J

Work input = 25J.

Therefore efficiency = 20/25 × 100 %

Efficiency = 20×4 %

Efficiency = 80%

I hope this was helpful, please mark as brainliest

3 0

3 years ago

A skiy diver, with parachute unopened, falls 625 m in 15.0s.

olganol [36]

Answer:

average velocity = 6.25m/sec

Explanation:

given data:

for unopened

height = 625 m

time = 15 sec

for opened

height = 356 m

time = 142 sec

Unopened:

$V1 = \frac{625\ m}{15\ sec} = 41.67m/sec$

Opened:

$V2 = \frac{356\ m}{142\ sec} = 2.51m/sec$

we know that

Total Average Velocity $= \frac{Total\ distance}{Total\ time}$

average velocity $= \frac{981\ m}{157\ sec}$

average velocity = 6.25m/sec

downward direction.

3 0

3 years ago

What is a tool that can be used to measure the size of a force

Gelneren [198K]

If the force is in the right range ... not too strong and not too
weak ... then a bathroom scale can be used to measure it.

If the force is huge, then you'd need a truck scale.

If the force is small, then you'd need a laboratory balance.

7 0

4 years ago

Read 2 more answers

A giant wall clock with diameter d rests vertically on the floor. The minute hand sticks out from the face of the clock, and its

Katyanochek1 [597]

Answer:

$d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)$

Explanation:

We can try writing the equation of the horizontal component of the length of the minute hand in terms of distance and the angle, that depends of time in this particular case.

The x-component of the length of the minute hand is:

$d_{x}(t)=dcos(\theta (t))$ (1)

d is the length of the minute hand (d=D/2)
D is the diameter of the clock
t is the time (min)

Now, using the angular kinematic equations we can express the angle in term of angular velocity and time. As we know, the minute hand moves with a constant angular velocity, so we can use this equation:

$\theta (t)=\omega *t$ (2)

Also we know, that the minute hand moves 90 degrees or π/2 rad in 15 min, so using the definition of angular velocity, we have:

$\omega=\frac{\Delta \theta}{\Delta t}=\frac{\theta_{f}-\theta_{i}}{t_{f}-t{i}}=\frac{\pi/2-0}{15-0}=\frac{\pi}{30}$

Now, let's put this value on (2)

$\theta (t)=\frac{\pi}{30}*t$

Finally the length x(t) of the shadow of the minute hand as a function of time t, will be:

$d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)$

I hope it helps you!

6 0

3 years ago