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Cloud [144]
3 years ago
6

Evaluate. 12+4⋅3−15 Enter your answer in the box.

Mathematics
2 answers:
Nina [5.8K]3 years ago
7 0

Answer:

the answer is 1.3

Step-by-step explanation:

12+4.3 is 16.3

16.3-15 is 1.3

Akimi4 [234]3 years ago
3 0

Answer:

9

Step-by-step explanation:

PEMDAS stands for Parenthesis, Exponents, Multiplication, Division, Addition, and Subtraction.

So, the first thing you would do is Multiply:

12+4*3-15

12+12-15

Then Add:

24-15

Finally Subtract:

9

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Find the coordinates of the missing endpoint if P is the midpoint of Line Segment NQ.
dimaraw [331]
  • Midpoint formula is (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) .
<h3>19.</h3>

So starting with this one, we will be solving for the coordinates of the unknown endpoint separately. Starting with the x-coordinate, since we know that the midpoint x-coordinate is 5 and the x-coordinate of N is 2, our equation is set up as such: \frac{x+2}{2}=5 From here we can solve for the x-coordinate of Q.

Firstly, multiply both sides by 2: x+2=10

Next, subtract both sides by 2 and your x-coordinate is x=8

With finding the y-coordinate, it's a similar process as with the x-coordinate except that we are using the y-coordinates of the midpoint and endpoint N.

\frac{y+0}{2}=2\\ y=4

<u>Putting it together, the missing endpoint is (8,4).</u>

<em>(The process is pretty much the same with the other problems, so I'll go through them real quickly.)</em>

<h3>20.</h3>

\frac{x+5}{2}=6\\ x+5=12\\ x=7

\frac{y+4}{2}=3\\ y+4=6\\ y=2

<u>The missing endpoint is (7,2).</u>

<h3>21.</h3>

\frac{x+3}{2}=-1\\ x+3=-2\\ x=-5

\frac{y+9}{2}=5\\ y+9=10\\y=1

<u>The missing endpoint is (-5,1).</u>

8 0
3 years ago
around a square with diagonal d = 4.6 cm a circle is described. Calculate the perimeter of the circle​
Nadya [2.5K]

Answer:

14.45cm2

Step-by-step explanation:

The diagonal is the diameter of the circle.

4.6cm

The perimeter of the circle is

Pi x4.6= 3.142 * 4.6= 14.45cm2

3 0
3 years ago
According to the rule of 72, t=72/r which statement is true?
nika2105 [10]
72/rate=time
72/9=8 years
So the answer is c
5 0
3 years ago
Read 2 more answers
3)
Wewaii [24]

Answer:

For covering  1 unit area of the entire playground, the amount of sand required is equal to volume of 3 buckets of sand.

Step-by-step explanation:

Given -

\frac{1}{3} volume of sand in bucket is able to cover \frac{1}{9} area of the entire playground

Thus,

For covering  \frac{1}{9} unit area of the entire playground, the amount of sand required is equal to  \frac{1}{3}  of the total volume of sand in bucket

For covering  1 unit area of the entire playground, the amount of sand required is equal to

\frac{\frac{1}{3} }{\frac{1}{9} } \\\\\frac{1}{3}  * \frac{9}{1} \\\frac{9}{3}\\= 3

For covering  1 unit area of the entire playground, the amount of sand required is equal to volume of 3 buckets of sand.

4 0
3 years ago
What is the value of 5(a + b) when a=1 and b=6 ​
lana [24]

Answer: 35

Step-by-step explanation:

We substitute a for 1 and b for 6.

5(1+6)=5(7)=35

5 0
3 years ago
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