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stellarik [79]
3 years ago
13

Help me please and thank you

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0

Area of the shape = 26.75 units²

Solution:

Base of the small triangle = 2 units

Height of the small triangle = 2 units

Area of the small triangle = \frac{1}{2}bh

                                          $=\frac{1}{2}\times2\times2

Area of the small triangle = 2 units²

Base of the medium triangle = 5 units

Height of the medium triangle = 2 units

Area of the medium triangle = \frac{1}{2}bh

                                          $=\frac{1}{2}\times5\times2

Area of the medium triangle = 5 units²

Side length of the square = 2 units

Area of the square = side × side

                                = 2 × 2

Area of the square = 4 units²

Base of the large triangle = 2 + 2 + 5 = 9 units

Height of the large triangle = 3.5 units

Area of the large triangle =  \frac{1}{2}bh

                                          $=\frac{1}{2}\times9\times3.5

Area of the large triangle = 15.75 units²

Area of the shape = Area of the small triangle + Area of medium triangle

                                 + Area of square + Area of large triangle

                              = 2 units² + 5 units² + 4 units² + 15.75 units²

                              = 26.75 units²

Area of the shape = 26.75 units²

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natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

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Answer:

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Step-by-step explanation:

(-3, 6) & (4,-2)

To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(-2 - 6) / (4 - (-3))

Simplify the parentheses.

= (-2 - 6) / (4 + 3)

= -8 / 7

Simplify the fraction.

= -8/7

This is your slope.

Hope this helps!

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Let the number be x.

Triple the number means 3x
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So, combining these into an equation, we get:
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If we solve this equation for x, we will get:
x + 6 = x + 3
The x will cancel out and we will get : 6 = 3

Therefore, this is a false statement.
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