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Yuri [45]
2 years ago
15

The base of an isosceles triangle is 7cm long. Each of the other sides is x cm long. What will be the expression for its perimet

er?
Mathematics
1 answer:
baherus [9]2 years ago
4 0

Answer:

P = 2x + 7

Step-by-step explanation:

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A rock is thrown upwards from the edge of a 52 foot cliff and eventually falls to the ground. The graph
Lina20 [59]
The rock's height is increasing in the interval from 0 seconds to 3 seconds.

At time 0 the rock starts moving upward from 52 foot until it reachs 180 foot height (time 3 seconds). Then the rock starts to descend, which means that the height starts to decrease.
5 0
3 years ago
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If B=3x^{2}-x+3 and A=x-6, find an expression that equals 2B+3A in standard form.
Ivan

9514 1404 393

Answer:

  6x^2 +x -12

Step-by-step explanation:

Substitute for A and B and collect terms.

  2B +3A

  = 2(3x^2 -x +3) +3(x -6) . . . . substitute for A and B

  = 6x^2 -2x +6 +3x -18 . . . . . eliminate parentheses

  = 6x^2 +x -12 . . . . . . . . . . . . collect terms

7 0
3 years ago
Can someone help me this question?
Vilka [71]

Answer:

The answer is B.

Step-by-step explanation:

5 0
3 years ago
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A restaurant owner installed a new automated drink machine. The machine is designed to dispense 530 mLof liquid on the medium si
lidiya [134]

Answer:

a.H0: μ =530mL vs. Ha: μ > 530mL

Step-by-step explanation:

-A hypothesis test will be used to provide evidence that the median is more or equal to the stated median value.

#In a normally distributed population, the mean=mode=median:

Mean=Mode=Median=\mu

-The null hypothesis states that the median is equal to the stated value:

H_o:\mu=530 \ mL

-The alternative hypothesis provides evidence that the median value is greater than the stated value:

H_a:\mu>530\ mL

Hence, the correct hypotheses are H0: μ =530mL vs. Ha: μ > 530mL

6 0
3 years ago
If f(x)= x/2-2 and g(x)= 2x^2+x-3, find (f+g)(x).
adelina 88 [10]

Answer: B. 2x^2 + \frac{3x}{2} - 5

Step-by-step explanation:

Here, the given functions are,

f(x) = \frac{x}{2} - 2

g(x) = 2x^2 + x - 3

(f+g)x = f(x) + g(x)

(f+g)x=\frac{x}{2} - 2 + 2x^2 + x - 3

(f+g)x=\frac{3x}{2} - 5 + 2x^2

(f+g)x=2x^2 + \frac{3x}{2} - 5

Option B is correct.

5 0
3 years ago
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