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2 years ago

15

The base of an isosceles triangle is 7cm long. Each of the other sides is x cm long. What will be the expression for its perimet

er?

1 answer:

baherus [9]2 years ago

4 0

Answer:

P = 2x + 7

Step-by-step explanation:

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Ashley took $20 out on her savings account each week on Friday. How many weeks ago did she have at least $250 in her account

Nookie1986 [14]

Since the question seems to either miss a variable, or is phrased wrong, I will answer with this. It will take 13 fridays, or 13 weeks for 20 to add up to a number greater than 250.<span />

4 0

3 years ago

What is the slope of the line passes through the pair of points (-4.1,7.4), (4.3,3.2)

Paladinen [302]

Hi there! The formula for finding the slope is y2 - y1/ x2 - x1. This means you subtract the first x and y-coordinates form the second x and y-coordinates. (-4.1, 7.4) is the first coordinate and (4.3, 3.2) is the second coordiante. Set it up like this:

3.2 - 7.4 / 4.3 - (-4.1)

Now, let's subtract. 3.2 - 7.4 is -4.2. 4.3 - (-4.1) is 9.4. -4.2/9.4 is -0.5 when simplified. There. The slope of the line is -0.5. The answer is C: -0.5.

Note: When you subtract a negative number, you're actually adding. So if an expression is 2 - (-3), the answer is 5, because you add 3 into 2.

3 0

3 years ago

How do I get this answer?

Keith_Richards [23]

Answer:

Step-by-step explanation:

Several trig identities are involved in the proof of this. This is the order in which they are used.

cos(2x) = cos²(x) -sin²(x)
cos²(x) +sin²(x) = 1
cos(x) = 1/sec(x)

<h3>Proof</h3>

Starting with the left side, we can transform it into the right side.

$2\cos(2x)=2(\cos^2(x)-\sin^2(x)) = 2(\cos^2(x)-(1-\cos^2(x)))\\\\=2(2\cos^2(x)-1)=2\left(\dfrac{2}{\sec^2(x)}-\dfrac{\sec^2(x)}{\sec^2(x)}\right)\\\\=\boxed{\dfrac{4-2\sec^2(x)}{\sec^2(x)}}$

4 0

2 years ago

I need the answer ASAP with give Brainlyest

nekit [7.7K]

M stands for the slope (change in Y/ change in X)

B stands for the y intercept

6 0

3 years ago

On a coordinate plane, an exponential function has a horizontal asymptote of y = 0. The function curves up into the first quadra

aleksandr82 [10.1K]

Answer:

The graph will show an initial value that is lower on the y-axis

Step-by-step explanation:

The exponential function has the next general form:

$y = ab^x$

where <em>a</em> is the initial amount and <em>b</em> is the base.

If the <em>a</em> value in the function is decreased, but remains greater than 0, the y-intercept of the curve decrease.

8 0

3 years ago

Read 2 more answers