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Yuri [45]
2 years ago
15

The base of an isosceles triangle is 7cm long. Each of the other sides is x cm long. What will be the expression for its perimet

er?
Mathematics
1 answer:
baherus [9]2 years ago
4 0

Answer:

P = 2x + 7

Step-by-step explanation:

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I need help with this math question
givi [52]

Answer:

a.) y = 3/(2ˣ)

b.) y = 1/(2ˣ)

c.) y = (π^π)ˣ

d.) y = (1/27)(1/√(3))ˣ

e.) y = .002908/(.119025ˣ)

f.) y = .00000004808/(.0413ˣ)

Step-by-step explanation:

Concept need to know is:

  • a negative exponent will flip the numerator with the denominator
  • a fraction as an exponent is just a root. so if the exponent is x^(1/2) then the root is 2 and x^(1/3) is a cube root
  • adding and subtracting exponent is the same thing as multiplying the same base.
  • so x^(1+2) = (x^1)(x^2)
  • and x^(1-2) = (x^1)(x^-2)

7 0
3 years ago
Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).
fomenos

Answer:

\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is 2a=|4--10|.

\implies 2a=|14|

\implies 2a=14

\implies a=7

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is (\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)

We need to use the relation a^2+b^2=c^2 to find b^2.

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

c=|6--3|=9

\implies 7^2+b^2=9^2

\implies b^2=9^2-7^2

\implies b^2=81-49

\implies b^2=32

We substitute these values into the standard equation of the hyperbola to obtain:

\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1

\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1

7 0
3 years ago
If the width and length of a rectangle are both increased by 10%, by what percent does the area of the rectangle increase?
S_A_V [24]

Answer:

10%

Step-by-step explanation:

We know Perimeter of rectangle

= 2 (Length + Width)

If width and length are increased by 10%

New length= L + 10/100L = (1.1) L

New width = W + 10/100W = (1.1) W

Perimeter = 2 [(1.1) L + (1.1) W]

Perimeter = 2 (1.1) (L + W)

Perimeter = (2.2) (L + W)

Increase in perimeter = 2.2 (L + W) - 2 (L + W)

The increase in Perimeter = 0.2 (L + W)

Percent increase

= 0.2 (L + W)/2 (L + W) × 100

= 0.2/2 × 100

= 0.1 × 100

= 10%

I hope this helped and if it did, please mark as Brainliest.

7 0
2 years ago
PLSSS HELP!! I'LL GIVE BRAINLIEST IF RIGHT Which is the equation of a parabola with a directrix at y = 2 and a focus at (5, 0).
goldfiish [28.3K]

Answer:

First, we need to set up a (y−k)^2=4p(x−h). After plugging in all of your values, you would get (x-5)^2=-4(y-1). Now, we need to solve in terms of y by dividing each side by the factors that don't contain the variable

Step-by-step explanation:

3 0
3 years ago
The scatterplot below shows the average yearly consumption of bottled water by people in the United States starting in 1990. Usi
lina2011 [118]
Where is the question chart/graph?
8 0
3 years ago
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