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Rudik [331]
3 years ago
12

The high-speed police chase ends at an intersection as a 2,150-kg Ford Explorer (driven by Robin) traveling south at 35 m/s coll

ides with a 18,250-kg garbage truck moving east at 1.55 m/s. The Explorer and the garbage truck entangle together in the middle of the intersection and move as a single object. Determine the post-collision speed two entangled vehicles.
Physics
1 answer:
defon3 years ago
4 0

Answer:

The post-collision speed of the two entangled vehicles is 5.08m/s

Explanation:

According to the law of conservation of momentum which states that the sum of momentum of a body before collision is equal to the sum of the collision of the bodies after collision. The bodies moves with the same velovity after collision.

Mathematically, mu + MU = (m+M)v

m and M are the masses of the bodies

u and U are their respective velocities

v is their common velocity

Momentum = mass*velocity

BEFORE COLLISION;

Momentum of Ford Explorer = 2150*35

= 75,250kgm/s

Momentum of the garbage truck = 18, 250 * 1.55

= 28,287.5kgm/s

AFTER COLLISION;

Note that the body will move with the same velocity after collision.

Momentum of the bodies after entangling = (2,150+18,250)v

= 20,400v kgm/s (v is their common velocity)

According to thr law;

75,250+28,287.5 = 20,400v

103,537.5 = 20,400v

v = 103,537.5/20,400

v = 5.08m/s

The post-collision speed of the two entangled vehicles is 5.08m/s

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A uniform solid disk with a mass of 24.3 kg and a radius of 0.364 m is free to rotate about a frictionless axle. Forces of 90.0
a_sh-v [17]

Answer:

a. -12.7 Nm

b. -7.9 rad/s^2

Explanation:

I have attached an illustration of a solid disk with the respective forces applied, as stated in this question.

Forces applied to the solid disk include:

F_1 = 90.0N\\F_2 = 125N

Other parameters given include:

Mass of solid disk, M = 24.3kg

and radius of solid disk, r = 0.364m

a.) The formula for determining torque (T), is T = r * F

Hence the net torque produced by the two forces is given as a summation of both forces:

T = T_{125} + T_{90}\\= -r(125)sin90 + r(90)sin90\\= 0.364(-125 + 90)\\= -12.7 Nm

b.)  The angular acceleration of the disk can be found thus:

using the formula for the Moment of Inertia of a solid disk;

I_{disk} = {\frac{1}{2}}Mr^2

where M = Mass of solid disk

and r = radius of solid disk

We then relate the torque and angular acceleration (\alpha) with the formula:

T = I\alpha \\-12.7 = ({\frac{1}{2}}Mr^2)\alpha \\\alpha  = -{\frac{12.7}{1.61}} = -7.9 rad/s^2

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Describe the motion represented by a horizontal line on a distance-time graph.
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Answer:

hi, this is the answer

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A horizontal line on a distance-time graph shows no change in distance, therefore there is no motion.

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Which is a property of ionic compounds?
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Read 2 more answers
Bryce, a mouse lover, keeps his four pet mice in a roomy cage, where they spend much of their spare time–when they\'re not sleep
Anit [1.1K]

Answer:

mice total momentum (-0.000250, 0.00639) Kg m

Explanation:

To calculate the moment of the mice we must multiply their mass by their velocities, remember that the moment is a vector quantity, so we use the components of velocity

mouse 1

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  V1 = (0.869, -0.283) m / s

 

  Px = m Vx

  Px1 = 0.0225 0.869

  Px1 = 0.01955 Kg m

  Py = m Vy

  Py1 = 0.0225 (-0.283)

  Py1 = -0.006368 Kg m

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Mouse 2

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 Px2 = 0.0223 (-0.883) = -0.0196 Kg m

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Mouse 3

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To find the total momentum we must add each component of the individual moments

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   Py = py1 + Py2 + Py3 + Py4

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   Py = 0.00639 Kg m

   P = (-0.000250, 0.00639) Kg m

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