Answer:
The post-collision speed of the two entangled vehicles is 5.08m/s
Explanation:
According to the law of conservation of momentum which states that the sum of momentum of a body before collision is equal to the sum of the collision of the bodies after collision. The bodies moves with the same velovity after collision.
Mathematically, mu + MU = (m+M)v
m and M are the masses of the bodies
u and U are their respective velocities
v is their common velocity
Momentum = mass*velocity
BEFORE COLLISION;
Momentum of Ford Explorer = 2150*35
= 75,250kgm/s
Momentum of the garbage truck = 18, 250 * 1.55
= 28,287.5kgm/s
AFTER COLLISION;
Note that the body will move with the same velocity after collision.
Momentum of the bodies after entangling = (2,150+18,250)v
= 20,400v kgm/s (v is their common velocity)
According to thr law;
75,250+28,287.5 = 20,400v
103,537.5 = 20,400v
v = 103,537.5/20,400
v = 5.08m/s
The post-collision speed of the two entangled vehicles is 5.08m/s
