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Charra [1.4K]
3 years ago
11

Which elements listed below are most likely to form anions? Select all that apply. Lithium (Li) Calcium (Ca) Sulfur (S) Fluorine

(F)
Physics
1 answer:
nadezda [96]3 years ago
7 0

Answer: Li, S, F

Explanation:

They are all non-metallic elements

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A 76 N crate is hung from a spring
lutik1710 [3]

Answer: 0.169 (3 s.f.)

Explanation:

Force = 76 N

Spring constant = 450 N/m

Extension/displacement = x

Hooke's law states that: F = kx

Therefore, 76 = 450 X x

76/450 = x

0.169 (3 s.f.) = x

4 0
3 years ago
The density of a substance can be found with the help of:
Bess [88]
Mass (m) and volume (v)
the equation is d = m/v
6 0
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Which. describe newtons law of univesel gravitation
Fed [463]

Newton's law of universal gravitation, says that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Or in simple words, every particle in the world attracts each other to themselves, but the particle with most mass would attract with more force compared to a particle with less mass.

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4 0
3 years ago
Worth 50 point!!!
olasank [31]

Answer:

Chief Hopper

Explanation:

Mike travels at a constant speed of 3.1 m/s.  To find how long it takes him to reach the school, we need to find the distance he travels.  We can do this using Pythagorean theorem.

a² + b² = c²

(1000 m)² + (900 m)² = c²

c ≈ 1345 m

So the time is:

v = d / t

3.1 m/s = 1345 m / t

t ≈ 434 s

Next, Chief Hopper travels a total distance of 1900 m, starting at rest and accelerating at 0.028 m/s².  So we can use constant acceleration equation to find the time.

d = v₀ t + ½ at²

1900 m = (0 m/s) t + ½ (0.028 m/s²) t²

t ≈ 368 s

So Chief Hopper reaches the school first, approximately 66 seconds before Mike does.

3 0
3 years ago
An airplane traveling at half the speed of sound emits a sound of frequency 5.84 kHz. (a) At what frequency does a stationary li
sergejj [24]

Answer:

Stationary listener frequency = 77.68 kHz

Explanation:

Given:

Speed of airplane = 344/2 = 172 m/s

Sound of frequency = 5.84 kHz

Computation:

f0 = fs[(v+v0)/(v-vs)]

f0 = 5.84[(344+0)/(344-172)]

f0 = 5.84[(344)/172]

Stationary listener frequency = 77.68 kHz

7 0
2 years ago
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