3 years ago

Find the area of the trapezoid. Leave your answer in simplest radical form. The figure is not

Mathematics

1 answer:

Irina18 [472]3 years ago

8 0

Answer:

Step-by-step explanation:

So you have to find the base of the trapezoid.

12 + 6 + 2 = 20

$\frac{12+20}{2} *6=96cm^2$

You might be interested in

0 3 8 15 24 35... What is the next value? The choices are 46, 48, 52, and 59.

Leto [7]

The next value would be 48. The values keep increasing by odd numbers. Like the first one is 3 then it goes to 5.

3, 5, 7, 9, 11, 13.....

7 0

3 years ago

How do you find the area of the regular figure

snow_lady [41]

Answer:

Length times width

Step-by-step explanation:

l*w

5 0

3 years ago

Read 2 more answers

17) x =<br> (6x-7)<br> (103-x)

Firlakuza [10]

Answer:

6B = F8

Step-by-step explanation:

5 0

3 years ago

Write an equation in point-slope form of a line that goes through the points (1,4) and (3,-10). Do not use any spaces in your an

olasank [31]

Answer:

y-4=-7(x-1) OR y-(-10)=-7(x-3)

Step-by-step explanation: The point-slope form is $y_$ - $y_{1}$ = $m_$ ( $x_$ - $x_{1}$ )

In slope-intercept form, the equation would be y = -7x + 11

You could find the slope by using the slope equation, $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$ .

Using that, you would get -7. Thus by inserting one of the points and the slope in the point-slope equation, you will get your answer.

6 0

3 years ago

If a simple harmonic motion is described by x = 3 cos(πt), starting from t = 0 s, what is the first occurrence of a value of t f

poizon [28]

Answer:

The first occurence of t for which x = 0 is t = 0.5.

Step-by-step explanation:

The harmonic motion is described by the following equation.

$x(t) = 3\cos{\pi t}$

What is the first occurrence of a value of t for which x = 0?

This is t when $x(t) = 0$ . So

$x(t) = 3\cos{\pi t}$

$3\cos{\pi t} = 0$

$\cos{\pi t} = \frac{0}{3}$

$\cos{\pi t} = 0$

The inverse of the cosine is the arcosine. So we apply the arcosine function to both sides of the equality.

$\arccos{\cos{\pi t}} = \arccos{0}$

$\pi t = \frac{\pi}{2}$

$t = \frac{\pi}{2 \pi}$

$t = \frac{1}{2}$

$t = 0.5$

The first occurence of t for which x = 0 is t = 0.5.

3 0

3 years ago