Answer:
Δ BEC ≅ Δ AED
Step-by-step explanation:
Consider triangles BCA and ADB. Each of them share a common side, AB. Respectively each we should be able to tell that AD is congruent to BC, and DB is congruent to CA, so by SSS the triangles should be congruent.
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So another possibility is triangles BEC, and AED. As you can see, by the Vertical Angles Theorem m∠BEC = m∠ADE, resulting in the congruency of an angle, rather a side. As mentioned before AD is congruent to BC, and perhaps another side is congruent to another in the same triangle. It should be then, by SSA that the triangles are congruent - but that is not an option. SSA does is one of the exceptions, a rule that is not permitted to make the triangles congruent. Therefore, it is highly unlikely that triangles BEC and AED are congruent, but that is what our solution, comparative to the rest.
Δ BEC ≅ Δ AED .... this is our solution
Answer:
I'm going to do 1 as an example and using what I've taught you, you have to do the rest. Hope my explanation helps.
Step-by-step explanation:
We are given the points (-2, -4) and (-1, -1)
We need to find the slope.
The equation to do so is y2 - y1 / x2 - x1
lest say:
-2 is x1
-4 is y1
-1 is x2
-1 is y2
-1 - (-4) / -1 - (-2)
3/1 = 3
slope (m) = 3
We already know the y-intercept is 2
The equation of a line is y = mx + b
For this problem we just have to substitute what we already know.
y = (slope)x + y-intercept
y = 3x + 2
*TIP*
If the y-intercept is negative, let's say: b = -5 (using slope 8)
the equation will be y = 8x - 5
Hope this helps. I wish you all the best. :)
Using vector concepts, it is found that:
The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.
<h3>How can a vector be represented in component notation?</h3>
Given a magnitude M and angle 
, then a vector V can be represented as follows in component notation:
In this problem, the magnitude and the angle are given, respectively, by:
Hence:
V = [12cos(143º), 12sin(143º)] = (-9.58, 7,22).
Which means a displacement of 9.58 miles to the west(negative x = west) and 7.22 miles to the north(positive y = north).
The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.
More can be learned about vectors at brainly.com/question/24606590
#SPJ1
Answer:
45 minutes
Step-by-step explanation:
distance / rate = time
27 miles / 36 miles/hr = .75 hr ( 45 minutes )
Answer:
The equation of circle is:
Solution:
The general form of equation is given as:
Where, "r" is radius of circle and (a, b) is center of circle
Given that center at (-2, 1)
a = -2 and b = 1
Substitute (a , b) = (-2, 1) and (x, y) = (-5, -3) in general equation
Substitute r = 5 and (a, b) = (-2, 1) in general equation
Thus the equation of circle is found
