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Aleksandr-060686 [28]
3 years ago
6

Can you help me with this?|a^2| if a<0

Mathematics
1 answer:
7nadin3 [17]3 years ago
3 0

Answer:

|(-a)²| = | a² | = a²

Step-by-step explanation:

absolute value is always positive number as well as any number squared so sign is positive no matter what

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Five years ago, Victor was twice as old as his daughter Anika. In 10 years, the sum of their ages will equal 90. Find their ages
frozen [14]

Answer: 45 and 25

Step-by-step explanation:

Given

Five years ago victor was twice as old as his daughter

Suppose the current age of victor and his daughter are x and y

For five years ago

\Rightarrow (y-5)=2(x-5)\\\Rightarrow y-5=2x-10\\\Rightarrow y=2x-5\\\Rightarrow 2x-y=5\quad \ldots(i)

In 10 years sum of their ages is 90

\Rightarrow (y+10)+(x+10)=90\\\Rightarrow x+y=70\quad \ldots(ii)

On solving (i) and (ii) we get

\Rightarrow x=25,y=45

So, the current age of victor is 45 and his daughter is 25

8 0
2 years ago
(a) Find parametric equations for the line through (1, 4, 4) that is perpendicular to the plane x − y + 2z = 7. (Use the paramet
Alex777 [14]

Answer:

x=1+t\\y=4-t\\z=4+2t

Step-by-step explanation:

A vector perpendicular to the plane ax+by+cz+d=0 is of the form (a,b,c).

So, a vector perpendicular to the plane x − y + 2z = 7 is (1,-1,2).

The parametric equations of a line through the point (x_0,y_0,z_0) and parallel to the vector (a,b,c) are as follows:

x=x_0+at\\y=y_0+bt\\z=z_0+ct

Put (x_0,y_0,z_0)=(1,4,4) and (a,b,c)=(1,-1,2)

Therefore,

x=1+t\\y=4-t\\z=4+2t

xy-plane:

Put z = 0 ⇒ t = -2 ⇒x = - 1 , y = 6

So, at point (-1,6,0)

yz-plane:

Put x = 0 ⇒ t = -1 ⇒ y = 5, z =2

So, at point (0,5,2)

xz-plane:

Put y = 0 ⇒ t = 4 ⇒ x = 5, z = 12

So, at point (5,0,12)

5 0
3 years ago
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