Answer:
D. ABE =CBD by SSS.
Step-by-step explanation:
Given that AB = BD and BE = BC, the lengths of AE and CD are equal to each other. Hence, triangles ABE and BCD are congruent by SSS Theorem. The answer is D.
Answer:
½log3 + ½logx
Step-by-step explanation:
½(log(3x))
½(log3 + logx)
½logx + ½log3
Answer:
a) t(n) = 8n -23
b) t(n) = 7n +24
c) t(n) = -30n +9
d) t(n) = 1.8n +7
Step-by-step explanation:
The general equation for the n-th term of an arithmetic sequence is ...
an = a1 +d(n -1)
Expanding this, we find ....
an = a1 +d·n -d = d·n +(a1 -d)
Comparing that to the form ...
an = m·n +b
we see that ...
m = d
b = (a1 -d)
If you're given a term other than a1, say ak, then you have ...
ak = d·k +(a1 -d)
(a1 -d) = ak -d·k
For a given term and common difference, we can write the desired equation as ...
t(n) = d·n +(ak -d·k) . . . . . . given t(k) = ak and d
__
Once again, it is convenient to use a spreadsheet to do the calculations for a number of different instances of this problem.
a) t(n) = 8n -23
b) t(n) = 7n +24
c) t(n) = -30n +9
d) t(n) = 1.8n +7
Answer:
14
Step-by-step explanation:
By the property of intersecting secants outside of the circle.
