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Alenkinab [10]
4 years ago
8

Given the reaction at equilibrium:

Mathematics
1 answer:
AVprozaik [17]4 years ago
8 0
I think answer is a. Please give me brainlest I hope this helps let me know if it’s correct or not
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MATH HARD SOMEONE PLEASE HELP
ivolga24 [154]

I can help just tell me equation

8 0
3 years ago
Hi I need help please I’ll give brainliesst to show ever helps and explains
saw5 [17]

Answer: 233.19

Step-by-step explanation:

equation to find volume: width x length x height

the left box:

(14-7) x 3.25 x 3.25= 73.9375 (round after adding)

the right box:

7 x 3.25 x 7= 159.25

73.9375 + 159.25= 233.1875

Round to nearest hundredth: 233.19

8 0
2 years ago
How many five-digit natural numbers contain exactly one 0?
Tems11 [23]
<h3>If this helped, PLEASE make this the BRAINLIEST answer!</h3>

0.4641. would be your answer

Adding up there are 41769 five digit numbers with atleast one zero in it. Therefore the probability that a five-digit number has at least one zero in it is 0.4641.

3 0
3 years ago
In recent years the mean number of miles driven per year by residents of a particular state was 11,568. A researcher wishes to t
aleksandrvk [35]

Answer:

The degrees of freedom are given by:

df =n-1= 62 -1=61

And we want to find a critical value on the t distribution with 61 degrees of freedom who accumulates 0.025 of the area on each tail and the critical value would be t_{\alpha/2}= \pm 2.00

And the rejection region would be |t_{calc}| >2.00

Step-by-step explanation:

Data given and notation  

\bar X=10822 represent the sample mean  

s=1741 represent the sample standard deviation

n=62 sample size  

\mu_o =11568 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean differs from 11568, the system of hypothesis would be:  

Null hypothesis:\mu =11568  

Alternative hypothesis:\mu \neq 11568  

The degrees of freedom are given by:

df =n-1= 62 -1=61

And we want to find a critical value on the t distribution with 61 degrees of freedom who accumulates 0.025 of the area on each tail and the critical value would be t_{\alpha/2}= \pm 2.00

And the rejection region would be |t_{calc}| >2.00

8 0
3 years ago
Jerry's softball team is made up of 23 players, and 11 of them are boys. on the team, what is the ratio of girls to boys?
DaniilM [7]

12:11 because 11 are boys and 12 are girls


5 0
4 years ago
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