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Artist 52 [7]
3 years ago
5

: David measured the floor of his storage unit, which is rectangular. ​It is 12 meters wide and 15 meters from one corner to opp

osite corner. ​ ​How long is the storage unit?
Mathematics
1 answer:
Mariulka [41]3 years ago
6 0

Answer: 9 meters

Step-by-step explanation:

A line between two opposite corners splits the floor into two right angled triangles, therefore we can use Pythagoras’ Theorem which is:

a^2 + b^2 = c^2

where c is the hypotenuse, and a and b are the other two sides.

Hypotenuse in this question is 15 metres while one side is 12 metres. The length will now be:

a^2 + b^2 = c^2

12^2 + b^2 = 15^2

b^2 = 15^2 - 12^2

b^2 = 225 - 144

b^2 = 81

b = ✓81

b = 9m

The length of the storage unit is 9m

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Building a is 160160 feet shorter than building
Serjik [45]
I assume the heights are 160 ft and 1480 ft.

The two heights are unknown, so we will use variable h to help solve the problem.
The shorter building, building A, has height h.
Since building A is shorter by 160 ft, then building B is taller by 160 ft, so the height of building B is h + 160.

Now we add our two heights to find the total height.

h + h + 160 is the total height.
We can write it as 2h + 160

We are told the total height is 1480 ft, so we let 2h + 160 equal 1480, and we have an equation.

2h + 160 = 1480

Subtract 160 from both sides

2h = 1320

Divide both sides by 2

h = 660

h + 160 = 820

Building A measures 660 ft.
building B measures 820 ft.
7 0
2 years ago
Please help thank you.
marusya05 [52]
This problem can be completed in 2 ways. Both are acceptable.

Option 1:


This is an isosceles trapezoid that can be divided into a rectangle and two congruent triangles.

The area of the rectangle is the base times the height.

9 \times 4=36

The area of one of the triangles is half the base times the height.

\dfrac{1}{2} \times 5 \times 4 = 10

The other triangle must have that area too.

36+10+10=56

The area is 56 square centimeters.

Option 2:

We can use the area formula for the trapezoid.

A=\dfrac{b_1+b_2}{2} \times h

Where b_1 is the length of the shorter base
and b_2 is the length of the longer base
and h is the height.

The length of the shorter base is 9.
The length of the longer base is 9+5+5, or 19.

The height is 4.

A=\dfrac{9+19}{2} \times 4

=56

Same answer. The area is 56 square centimeters.

Both options are two acceptable ways the problem can be tackled.
7 0
3 years ago
Let F be a field, and suppose a EF, a *0. Prove that a has a unique multiplicative inverse.
bezimeni [28]

Answer with Step-by-step explanation:

Let F be a field .Suppose a\in F and a\neq 0

We have to prove that a has unique multiplicative inverse.

Suppose a has two inverses b and c

Then, ac=1,ab=1 where 1 =Multiplicative identity

ac=ab

c=b (cancel a on both sides)

Hence, a has unique multiplicative inverse.

6 0
3 years ago
A rectangular photo frame covers an area of 20 square inches on a wall. The width of the frame is 1 inch less than its length. F
Salsk061 [2.6K]
You need to find two factors of 20 that are consecutive: 4,5.
Answer: 5inx4in
7 0
3 years ago
At 6:00 PM, a flagpole that is 35 feet tall casts a shadow that is 50 feet long. At the same time, how long will a person's shad
sertanlavr [38]

<u>Answer:</u>

The length of the person’s shadow is 5.7ft

<u>Explanation:</u>

Length of the flagpole =a= 35ft

Length of the shadow of the flagpole= b=50ft

Length of the person=c= 4ft

Suppose the length of the person’s shadow is=d

According to the  rules of trigonometry

\frac{\text { Length of the flagpole }}{\text { Length of the shadow of the flagpole }}=\frac{\text { Length of the person }}{\text { Length of the person's shadow }}

\frac{a}{b}=\frac{c}{d}

\frac{35}{50}=\frac{4}{d}

35d=200

d=\frac{200}{35}

d=5.7ft  

Hence, The length of the person’s shadow is 5.7ft.

3 0
3 years ago
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