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3 years ago

14

What is the magnetic force on a 200 cm length of (straight) wire carrying a current of 30 A in a region where a uniform magnetic

field has a magnitude of 0.055 T and is directed at an angle of 20 away from the wire

1 answer:

Bezzdna [24]3 years ago

3 0

Answer:

F = 0.112 N

Explanation:

To find the magnitude of magnetic force on the wire, you use the following formula:

$|\vec{F}|=|i\vec{L}\ X\ \vec{B}|=iLBsin\theta$ (1)

L: length of the wire = 200cm = 0.2m

i: current in the wire = 30 A

B: magnitude of the magnetic field = 0.055 T

θ: angle between the directions of L and B = 20°

You replace the values of L, i, B and θ in the equation (1):

$|\vec{F}|=(30A)(0.2m)(0.055T)sin(20\°)=0.112N$

hence, the magnetic force on teh wire is 0.112N

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When the hydraulic conductivity Ks = 10 mm/hr; effective matrix potential Ns = 20 mm, and rainfall intensity I = 30 mm/hr , dete

Maslowich

Answer:

$t = 0.75 \ hr = 0.75 *60 = 45 \ minutes$

Explanation:

From the question we are told that

The hydraulic conductivity is $Ks = 10\ mm/hr$

The effective matrix potential $Ns = 20 \ mm$

The intensity of rainfall is $I = 30 \ mm/hr$

The runoff rate $R = 15 \ mm/hr$

Generally the run off rate is mathematically represented as

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Here t is the amount of runoff generated

=> $15 = (30 - 10) t$

=> $t = 0.75 \ hr$

converting to minutes

$t = 0.75 \ hr = 0.75 *60 = 45 \ minutes$

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3 years ago

What force is necessary to accelerate a 50kg box at 30 m/s2?

sammy [17]

Answer:

F = m X a

Therefore ,

Force required = 50 X 30 = 1500 newton

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3 years ago

A student decides to give his bicycle a tune up. He flips it upside down (so there's no friction with the ground) and applies a

aleksklad [387]

Answer:

$V=9.2565m/s$

Explanation:

From the question we are told that:

Force $F = 34 N$

Time $t = 0.6 s$

Length of pedal $l_p=16.5cm \approx0.165m$

Radius of wheel $r = 33 cm = 0.33 m$

Moment of inertia, $I = 1200 kgcm2 = 0.12 kg.m2$

Generally the equation for Torque on pedal $\mu$ is mathematically given by

$\mu=F*L\\\mu=34*0.165$

$\mu=5.61N.m$

Generally the equation for angular acceleration $\alpha$ is mathematically given by

$\alpha=\frac{\mu}{l}$

$\alpha=\frac{5.61}{0.12}$

$\alpha=46.75$

Therefore Angular speed is \omega

$\omega=\alpha*t$

$\omega=(46.75)*(0.6)$

$\omega=28.05rad/s$

Generally the equation for Tangential velocity V is mathematically given by

$V=r\omega$

$V=(0.33)(28.05)$

$V=9.2565m/s$

5 0

3 years ago

A person stands on a scale in an elevator. As the elevator starts, the scale has a constant reading of 592 N. As the elevator la

gladu [14]

Answer:

<h2>a) 496N</h2><h2>b) 50.56kg</h2><h2>c) 1.90m/s²</h2>

Explanation:

According to newton's secomd law, ∑F = ma

∑F is the summation of the force acting on the body

m is the mass of the body

a is the acceleration

Given the normal force when the elevator starts N1 = 592N

Normal force after the elevator stopped N2 = 400N

When the elevator starts, its moves upward, the sum of force ∑F = Normal (N)force on the elevator - weight of the person( Fg)

When moving up;

N1 - Fg = ma

N1 = ma + Fg ...(1)

Stopping motion of the elevator occurs after the elevator has accelerates down. The sum of forces in this case will give;

N2 - Fg = -ma

N2 = -ma+Fg ...(2)

Adding equation 1 and 2 we will have;

N1+N2 = 2Fg

592N + 400N = 2Fg

992N 2Fg

Fg = 992/2

Fg = 496N

The weight of the person is 496N

<em>\b) To get the person mass, we will use the relationship Fg = mg</em>

g = 9.81m/s

496 = 9.81m

mass m = 496/9.81

mass = 50.56kg

c) To get the magnitude of acceleration of the elevator, we will subtract equation 1 from 2 to have;

N1-N2 = 2ma

592-400 = 2(50.56)a

192 = 101.12a

a = 192/101.12

a = 1.90m/s²

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4 years ago

A current of 200 mA through a conductor converts 40 joules of electrical energy into heat in 30 second

Komok [63]

Answer:

V = 6.65 [volt]

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First, we must calculate the power by means of the following equation, where the voltage is related to the energy produced or consumed in a given time.

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Using the power we can calculate the voltage, by means of the following equation that relates the voltage to the current.

$P=V*I$

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V = voltage [Volts]

I = current = 200 [mA] = 0.2 [A]

$V = 1.33/0.2\\V = 6.65 [volt]$

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3 years ago