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SVEN [57.7K]
3 years ago
14

What is the magnetic force on a 200 cm length of (straight) wire carrying a current of 30 A in a region where a uniform magnetic

field has a magnitude of 0.055 T and is directed at an angle of 20 away from the wire
Physics
1 answer:
Bezzdna [24]3 years ago
3 0

Answer:

F = 0.112 N

Explanation:

To find the magnitude of magnetic force on the wire, you use the following formula:

|\vec{F}|=|i\vec{L}\ X\ \vec{B}|=iLBsin\theta   (1)

L: length of the wire = 200cm = 0.2m

i: current in the wire = 30 A

B: magnitude of the magnetic field = 0.055 T

θ: angle between the directions of L and B = 20°

You replace the values of L, i, B and θ in the equation (1):

|\vec{F}|=(30A)(0.2m)(0.055T)sin(20\°)=0.112N

hence, the magnetic force on teh wire is 0.112N

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Also here's a neat trick:

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10 seconds.

Explanation:

We can use a kinematic equation where we know the final velocity, initial velocity, acceleration, and need to determine the time <em>t: </em>

<em />\displaystyle v_f = v_i + at<em />

<em />

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Substitute and solve for <em>t: </em>

<em />\displaystyle \begin{aligned} (0\text{ m/s}) & = (30 \text{ m/s}) + (-3 \text{ m/s$^2$}) t \\ \\  t & = \frac{-30\text{ m/s}}{-3 \text{ m/s$^2$}} \\ \\ & = 10 \text{ s} \end{aligned}<em />

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Hence, it will take the car 10 seconds to come to a stop.

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Glass is transparent to visibile light under normal conditions; however, at extremely high intensities, glass will absorb most o
8_murik_8 [283]

Answer:

3 photons

Explanation:

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E=\frac{hc}{\lambda}

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