T2=r In the form of Kepler's law that can use to relate the period T and radius of the planet in our solar systems
<u>Explanation:</u>
<u>Kepler's third law:</u>
- Kepler's third law states that For all planets, the square of the orbital
period (T) of a planet is proportional to the cube of the average orbital radius (R).
- In simple words T (square) is proportional to the R(cube) T²2 ∝1 R³3
- T2 / R3 = constant = 4π ² /GM
where G = 6.67 x 10-11 N-m2 /kg2
M = mass of the foci body
Velocity would be an answer
Answer:
1.68N
Explanation:
W=F*d
KE=1/2*M*V^2
M=32kg
V= 5.1m/s
D=50m
0.5(32)(5.1^2)= 416 J
Initial energy=500 J
final energy= 416 J
lost energy= 500-416
heat lost to friction=84 J
84=F*50
84/50=F*50/50
F=1.68N
Answer it's 1,445 A
Explanation:
Basically 9,875 - what will give you 8,430 that's what's its asking. Its just a gap.
Answer: it’s in the picture
Explanation: look at the picture
