Answer:
<em>The range is 15.15 m and the time in the air is 1.01 s</em>
Explanation:
<u>Horizontal Motion</u>
When an object is thrown horizontally (with angle 0°) with a speed v from a height h, it follows a curved path ruled exclusively by gravity until it eventually hits the ground.
The range or maximum horizontal distance traveled by the object can be calculated as follows:
To calculate the time the object takes to hit the ground, we use the equation below:
The cannon is shot from a height of h=5 m with an initial speed of v=15 m/s. The range is calculated below:
d = 15.15 m
The time in the air is:
t = 1.01 s
The range is 15.15 m and the time in the air is 1.01 s
Answer:
My answer is when the ball is going it experience kinetic energy which is the energy of a moving object while when the ball has stopped then it will have potential energy which means it's at rest so for the ball not to experience friction then there is a gain in kinetic energy and decrease in potential energy.
Answer:
H = 27.35 m
Explanation:
From projectile motion, we know that;
h = (v_o)²/2g
Where;
v_o = 12 m/s
g = 9.8 m/s²
Thus;
h = 12²/(2 × 9.8)
h = 144/19.6
h = 7.35 m
Now, we are told that when the man is 20 m above the pillow, he lets go of
the rope.
Thus, greatest height reached by the man above the ground is;
H = 20 + h
H = = 20 + 7.35
H = 27.35 m
60,000 meters. no explanation
Answer:
4 days
either multiply 128 by .5 until you get to 2 counting each time or use 2 formulas ln(n2/n1)=-k(t2-t1) to get k then input k into ln(2)=k*t1/2
n2 is final amount and n1 is beginning and t is either time elapsed as in the first formula or the actual half life that is t1/2
Explanation:
