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Simora [160]
3 years ago
12

A planet orbits a star, in a year of length 2.35 x 107 s, in a nearly circular orbit of radius 3.49 x 1011 m. With respect to th

e star, determine (a) the angular speed of the planet, (b) the tangential speed of the planet, and (c) the magnitude of the planet's centripetal acceleration.
Physics
1 answer:
Naya [18.7K]3 years ago
7 0

Answer:

a)   w = 9.599 10⁴ rad / s , b)   v = 3.35 10¹⁶ m / s , c)    a = 3.22  10²¹ m / s²

Explanation:

For this exercise we must use the relation of angular kinematics

a) angular velocity, the distance remembered in orbit between time (period)

         w = 2π r / T

         w = 2 π 3.59 10¹¹ / 2.35 10⁷

         w = 9.599 10⁴ rad / s

b) linear and angular velocity are related by the equation

          v = w r

          v = 9,599 10⁴ 3.49 10¹¹

          v = 3.35 10¹⁶ m / s

c) the centripetal acceleration is

            a = v² / r = w² r

            a = (9,599 10⁴)²   3.49 10¹¹

            a = 3.22  10²¹ m / s²

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tekilochka [14]

Answer:

a) It takes 6,37 s b) The Velocity is -59,43 m/s

Explanation:

The initial variables of the balloon are:

Xo = 0 m

Vo = 3 m/s

After one minute the situation is the following:

t= 60 s

X1 = Xo + Vo*t

X1= 0 m + 3 m/s * 60s

X1= 180m

So when the bag falls, its initial variables are the following:

Xo = 180m

X1 = 0m

Vo = 3 m/s

V1= ?

a= -9,8 m/s2

The ecuation of movement for this situation is:

X = Vo*t + 1/2 a*t^{2}

So:

-180m = 3m/s*t+ 1/2*-9,8 m/s2 * t^{2}

To solve this we have

a=-9,8/2

b=3

c=180

The formula is:(-b +/- \sqrt{b^{2} -4ac}) /2a

Replacing, we get to 2 solutions, where only the positive one is valid because we are talking about time.

<u>So the answer a) is t= 6,37 s</u>

With that answer we can find the question b), with the following movement formula.

Vf = Vo + at

Vf = +3 m/s + (-) 9,8 m/s2 *6,37s

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5 0
3 years ago
In a particular case of Compton scattering, a photon collides with a free electron and scatters backwards. The wavelength after
mafiozo [28]

Answer:

hence initial wavelength is \lambda =4.86\times10^{-12}m

Explanation:

shift in wavelength due to compton effect is given by

\lambda ^{'}-\lambda =\frac{h}{m_{e}c}\times(1-cos\theta )

λ' = the wavelength after scattering

λ= initial wave length

h= planks constant

m_{e}= electron rest mass

c= speed of light

θ= scattering angle = 180°

compton wavelength is

\frac{h}{m_{e}c}= 2.43\times10^{-12}m

\lambda '-\lambda =2.43\times10^{-12}\times(1-cos\theta )

\lambda '-\lambda =2.43\times10^{-12}\times(1+1 )  ( put cos 180°=-1)

also given λ'=2λ

putting values and solving we get

\lambda =4.86\times10^{-12}m

hence initial wavelength is \lambda =4.86\times10^{-12}m

4 0
4 years ago
What is the equivalent resistance of a 7ohm resistor and a 93 ohm resistor connected in parallel? PLEASE HELP ASAP​
lukranit [14]

When you have several resistors in parallel, their equivalent resistance is the reciprocal of the sum of their individual reciprocals.

When there are only two of them, it gets a lot easier.  In that case, their equivalent resistance is equal to

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Equivalent = (7 x 93) / (7 + 93)

Equivalent = (651) / (100)

<em>Equivalent = 6.51 ohms </em>.

7 0
4 years ago
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Answer:

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3 0
3 years ago
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Answer:

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HAVE A GOOD DAY!

8 0
3 years ago
Read 2 more answers
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