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Serjik [45]
3 years ago
7

If chris throws a baseball 60 meters in 4 seconds, what is the average speed of the football?

Physics
1 answer:
IceJOKER [234]3 years ago
6 0
The average speed of the football is 15 meters per second. Just divide both of the numbers by 4 :)
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How solar panels are effective for sprayers?​
vichka [17]

Answer:

Solar pesticide sprayer can give less tariff or price in effective spraying. Solar energy is absorbed by the solar panel which contains photovoltaic cells. ... This converted energy utilizes to store the voltage in the DC battery and that battery further used for driving the spray pump.

Explanation:

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6 0
3 years ago
A 100 V battery is connected across a
Sergio039 [100]

1 mA = 0.001 A

Therefore, 5 mA = 0.001 * 5

=0.005 A

Resistance = voltage / current

= 100 / 0.005

= 20000 ohms

Current = voltage / resistance

= 25 / 20000

= 0.00125 A (or) 1.25 mA

5 0
3 years ago
A block with mass m1 = 8.8 kg is on an incline with an angle θ = 41.0° with respect to the horizontal. For the first question th
serg [7]
So based on your question where there is a block of mass m1= 8.8kg in the inclined plane with an angle of 41 with respect to the horizontal. To find the spring constant of the problem were their is a coefficients of friction of 0.39 and 0.429, you must use the formula K*x^2=m*a*sin(angle). By calculating the minimum spring constant is 220.66 N/m^2
6 0
3 years ago
A gamma ray burst produces radiation that has a period of 3.6x10-21 s. What wavelength does this radiation have?
Olin [163]

Answer:

The radiation wavelength is  1.08 X 10⁻¹² m

Explanation:

Frequency is the ratio of speed of photon to its wavelength

F = c/λ

where;

c is the speed of the photon = 3 x 10⁸ m/s

λ is the wavelength of gamma ray = ?

F is the frequency of the gamma ray = 1/T

T is the period of radiation = 3.6x10⁻²¹ s

\frac{1}{T}  = \frac{c}{\lambda}

λ = T*C

λ = 3.6x10⁻²¹ *  3 x 10⁸

λ =  1.08 X 10⁻¹² m

Therefore, the radiation wavelength is  1.08 X 10⁻¹² m

6 0
3 years ago
At 600.0 k the rate constant is 6.1× 10–8 s–1. what is the value of the rate constant at 785.0 k?
photoshop1234 [79]
Missing details. Complete text is:"The following reaction has an activation energy of 262 kJ/mol:
C4H8(g) --> 2C2h4(g)
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 785.0 K?"
To solve the exercise, we can use Arrhenius equation:
\ln( \frac{K_2}{K_1} ) =  \frac{Ea}{R} ( \frac{1}{T_1}- \frac{1}{T_2}  )
where K are the reaction rates, Ea is the activation energy, R=8.314 J/mol*K and T are the temperatures. Using T1=600 K and T2=785 K, and Ea=262 kJ/mol = 262000 J/mol, on the right side of the equation we have
\frac{Ea}{R}( \frac{1}{T_1}- \frac{1}{T_2}  )=12.38
And so
\ln( \frac{K_2}{K_1})=12.38
And using K_1=6.1\cdot 10^{-8} s^{-1} , we find K2:
K_2=K_1 e^{12.38}=0.0145 s^{-1}


5 0
3 years ago
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