Answer:
B meet A 0.01 km east of flagpole
Explanation:
given data
distance A = 5.7 km west
velocity V1 = 8.9 km/h
distance B = 4.5 km east
velocity V2 = 7 km/h
to find out
How far runners from the flagpole, when paths cross
solution
we know A and B are 5.7 + 4.5 = 10.2 km apart
and we consider here B will run distance x km for meet
so time will be for B is
time B = distance / velocity
time B = x / 7 ...................1
and
for A distance for meet = ( 10.2 - x ) km
so time A = distance / velocity
time A = ( 10.2 - x ) / 8.9 .............2
now equating equation 1 and 2
time A = time B
x / 7 = ( 10.2 - x ) / 8.9
x = 4.490
so distance of B run for meet is 4.490 km
so distance from the flagpole when their paths cross is 4.5 - 4.490 = 0.01 km
so B meet A 0.01 km east of flagpole
Explanation:
Below is an attachment containing the solution.
energy associate with position or shape
Answer:
Temperature will be 305 K
Explanation:
We have given The asteroid has a surface area 
Power absorbed P = 3800 watt
Boltzmann constant 
According to Boltzmann rule power radiated is given by




So temperature will be 305 K
1.46m/s²
Explanation:
Given parameters:
Mass of cart = 281kg
Net external force = 411N
Unknown:
Acceleration of the cart = ?
Solution:
According to newton's second law " the net force on a car is the product of its mass and acceleration";
Force = mass x acceleration
Since acceleration of the cart is unknown;
Acceleration =
= 
Acceleration = 1.46m/s²
learn more:
Newton's laws brainly.com/question/11411375
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