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3 years ago

This month carla caught the following fish in lake george will mark brainliest

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

5 0

Answer:

The fish could be a seafish.

Step-by-step explanation:

Seafishes are fishes that live in the sea most of the time.

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Please help me, I am so confused. Thanks

miskamm [114]

Answer:

c. 80

Step-by-step explanation:

cos x = sin(x-70)

cos x = cos [90-(x-70)]

cos x = cos (90-x +70)

cos x = cos 160 -x

x= 160-x

2x = 160

x =80

8 0

3 years ago

PLEASE HELP!!

Musya8 [376]

Answer:

x = - 33

Step-by-step explanation:

Given

$\frac{2}{3}$ (x + 6) = - 18

Multiply both sides by 3 to clear the fraction

2(x + 6) = - 54 ( divide both sides by 2 )

x + 6 = - 27 ( subtract 6 from both sides )

x = - 33

6 0

3 years ago

Read 2 more answers

Please help due in less than 3 hours!!!!!!!! When Anne biked down the canyon, she averaged 30 miles per hour. At this rate, how

bixtya [17]

Answer:

2 min.

Step-by-step explanation:

1h is 60 min so divide 60 by 30 and you get 2

3 0

3 years ago

Read 2 more answers

Fill in the missing fraction or mixed number __ + 1/4 = 5/8

gogolik [260]

3/8=answer

1) 5/8-1/4=

2) (5•4)-(1•8)=

8•4

3) 20-8

32 =

4) 12

32=

5) 12/4

32/4=

6) 3

8 =answer

5 0

3 years ago

please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me

mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH= $\sqrt{(5-0)^{2}+(1-1)^{2}}=5$ and

GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$

Now, mid point of JH= $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

= $(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)$

Mid point of GI= $(\frac{5}{2},1)$

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

$(GI)^{2}=(IJ)^{2}+(JG)^{2}$ (1)

Now, JI= $\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20}$ and GJ= $\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}$

Substituting these values in (1), we get

$5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }$

$25=20+5$

$25=25$

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$ and HJ= $\sqrt{(0-5)^2+(1-1)^2}=5$ are equal, thus, GHIJ is a rectangle.

6 0

3 years ago