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qaws [65]
3 years ago
6

How do I find the area of the shaded blue region?

Mathematics
1 answer:
kogti [31]3 years ago
3 0

That's a 240 degree sector of a 9 inch radius circle.  The whole circle has area πr² and we want 240/360 of it.

A = (240/360) π (9²) = 54 π

Answer: 54 π square inches

That's the exact answer.  An approximation is

169.646 square inches

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Two trains arrived at a station at 2:55 p.m., with one arriving on track a, and the other arriving on track
Sladkaya [172]
In 144 minutes, or at 5:19 pm, the trains will arrive at the same time again.
3 0
3 years ago
Read 2 more answers
1, 5, 17, 53, ... Use inductive reasoning to create a general rule for the sequence. A. Multiply by 3, then add 2. B. Multiply b
Basile [38]
The answer to this problem is the letter "A" which is "Multiply by 3, then add 2"
and can be written a N = 3n + 2
At first, we have initial value such n = 1
Then the second value is:
N = 3*1 + 2
N = 5
The third value is:
N = 3*5 + 2
N=17
The next values are:
N = 3*17 + 2
N= 53
The letter "A" is the inductive reasoning to the given sequence.
6 0
3 years ago
What is the compund interest on 5,000 over 3 years at 5% interest
Katena32 [7]

Answer:

788.13  to the nearest hundredth.

Step-by-step explanation:

Let A be the total amount in the account after 3 years.

The formula is A = P(1 + x/100)^t .

Here P = 5000, x = 5 %  and the time t = 3. years.  

Amount after 3 years = 5000(1 + 5/100)^3

=  5788.13

So the Interest is 5788.13 - 5000

= 788.13.

8 0
3 years ago
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Find the GCF (greatest common factor) of 8 and 7.
FrozenT [24]

Answer: Its 1

Step-by-step explanation:

4 0
2 years ago
Gravel is being dumped from a conveyor belt at a rate of 30 ft3/min, and its coarseness is such that it forms a pile in the shap
pogonyaev

Answer:

Rate of increase in height =\frac{dh}{dt}=0.3156ft/min

Step-by-step explanation:

we know that volume of a cone is given by

V=\frac{1}{12}\pi d^{2}h

It is Given that diameter equals height thus we have

V=\frac{1}{12}\pi h^{2}h\\\\V=\frac{1}{12}\pi h^{3}

Differentiating both sides with respect to time we get

\frac{dV}{dt}=\frac{1}{12}\pi \frac{dh^{3}}{dt}\\\\\frac{dV}{dt}=\frac{1}{12}\pi(3h^{2}\frac{dh}{dt})

Applying values and solving for \frac{dh}{dt} we get

\frac{dh}{dt}=\frac{12\frac{dV}{dt}}{3\pi h^{2}}\\\\\frac{dh}{dt}=0.3156ft/min

8 0
3 years ago
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