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ValentinkaMS [17]
3 years ago
11

write correct if the operations are listed in the correct order. if not correct, write the correct order of operations. 3x4÷2 di

vide, multiply
Mathematics
2 answers:
jeka943 years ago
7 0

Hi!

This question is about "order of operations on math, its super easy".

Hint: PEMDAS

Parenthesis is going to be first.

Exponents is going to be second.

Multiply is going to be third.

D-Divide is going to be fourth.

A-Add is going to be fifth.

S-Subtract is going to be sixth.

<u><em>That came from left to right.</em></u>

3*4/2

12/2

=6

Hope this helps you! Thank you for posting your question at here on Brainly. Have a great day! :)

-Charlie


Gemiola [76]3 years ago
3 0
PEMDAS applies, so it should be multiply, then divide.
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Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. Limit Interval lim
geniusboy [140]

Answer:

The corresponding definite integral may be written as

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x

The answer of the above definite integral is

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98

Step-by-step explanation:

The given limit interval is

\lim_{||\Delta|| \to 0}  \sum\limits_{i=1}^n (4c_i + 11) \Delta x_i

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The corresponding definite integral may be written as

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x

\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x

Bonus:

The definite integral may be solved as

\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98

Therefore, the answer to the integral is

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x  = 98

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