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DaniilM [7]
3 years ago
8

Question 3 Multiple Choice Worth 4 points) Simplify 11 ^ -4/ 11 ^ 8 HELP PLEASE

Mathematics
2 answers:
bulgar [2K]3 years ago
8 0

We can use the quotient rule to solve: a^b/a^c = a^b-c

= 11^-4/11^8

= 11^-4-8

= 11^-12

Use rule where a^-b = 1/a^b

= 1/11^12

Best of Luck!

AlekseyPX3 years ago
3 0

Answer:

11^ -12 = 1/ 11^12

Step-by-step explanation:

11^ -4  / 11^8

We know that a^b  / a^c   = a^(b-c)

11^ (-4 -8)

11^ -12

We also normally do not leave negative exponents

a^ -b = 1/ a^b

1/ 11^12

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Debora [2.8K]
The first incorrect is the second step so choice B. ,bc. the exponents need assuming not multiply 

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8 0
3 years ago
What are the coordinates of point F? On a coordinate plane, point F is 4 units to the right and 2.5 units down.
levacccp [35]

Answer:

(4,-2.5)

Step-by-step explanation:

because you move to the right it is a positive x-axis point and since you are moving down it is a negative y- axis point

6 0
2 years ago
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A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
3 years ago
Am I correct?<br><br> Which graph represents the line y= 1/5x
lara31 [8.8K]
Yes. Slope = rise over run so you go up one, over five
5 0
3 years ago
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Please help me. Urgent!!!
zlopas [31]

Answer:

Your answer would be A

The site Math-way is a good tool for this

4 0
3 years ago
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