All categories

3 years ago

Question 3 Multiple Choice Worth 4 points) Simplify 11 ^ -4/ 11 ^ 8 HELP PLEASE

Mathematics

2 answers:

bulgar [2K]3 years ago

8 0

We can use the quotient rule to solve: a^b/a^c = a^b-c

= 11^-4/11^8

= 11^-4-8

= 11^-12

Use rule where a^-b = 1/a^b

= 1/11^12

Best of Luck!

AlekseyPX3 years ago

3 0

Answer:

11^ -12 = 1/ 11^12

Step-by-step explanation:

11^ -4 / 11^8

We know that a^b / a^c = a^(b-c)

11^ (-4 -8)

11^ -12

We also normally do not leave negative exponents

a^ -b = 1/ a^b

1/ 11^12

You might be interested in

Denise goes to work with her father. She notices that one man worked 31 1\ 4 hours for the week, and he was paid $9.20 per hour.

pochemuha

Answer:

$287.50

Step-by-step explanation:

31.25 x 9.20 = $287.50

5 0

3 years ago

Read 2 more answers

2x^2=9-3x <br> Find the factors

d1i1m1o1n [39]

Answer:

x = -3, $\frac{3}{2}$

Step-by-step explanation:

The given quadratic equation is: $2x^2 = 9 - 3x$

This can be written as: $2x^2 + 3x - 9 = 0$

To solve a quadratic equation of the form $ax^2 + bx + c = 0$ we use the formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)}$

$\implies x = \frac{-3 \pm \sqrt{81}}{4}$

$\implies x = \frac{-3 \pm 9}{4}$

We get two values of 'x', viz.,

x = $\frac{-3 + 9}{4}$ and $\frac{- 3 - 9}{4}$

$\implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4}$

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $\frac{3}{2}$ ) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $\frac{3}{2}$ to see that this indeed is the given quadratic equation.

5 0

2 years ago

Mary is also a civil engineer, and she is building a triangular community garden. She knows two angles in the triangular garden,

pantera1 [17]

Answer:

A= 61

B=119

Step by step:

a; interior angle

180-(27+92)

=180(119)

=61

b; exterior angle

180-61

=119

7 0

2 years ago

Read 2 more answers

When 5x^2 + 2= 4x is written in standard form, what are the values of a, b, and c

goblinko [34]

The standard form of a quadratic equation is

$ax^{2}+bx+c=0$ ,

where $a$ , $b$ , and $c$ are coefficients. You want to get the given equation into this form. You can accomplish this by putting all the non-zero values on the left side on the equation.

In this case, the given equation is

$5x^{2}+2=4x$

Since $4x$ is on the right side of the equation, we subtract that from both sides. The resulting equation is

$5x^{2}-4x+2=0$

Looking at the standard form equation $ax^{2}+bx+c=0$ , we can see that

$a=5, b=-4, c=0$

7 0

2 years ago

If r=5(12,80) what the given radius and center

Mashutka [201]

I thik the answer is 64

6 0

2 years ago