A triangle has a leg with a length of 3 and a hypotenuse with a length of 6.What is the length of the other leg?

Mathematics

1 answer:

taurus [48]3 years ago

3 0

Answer:

3 $\sqrt{3}$

Step-by-step explanation:

Using Pythagoras' identity on the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x be the length of the other leg, then

x² + 3² = 6², that is

x² + 9 = 36 ( subtract 9 from both sides )

x² = 27 ( take the square root of both sides )

x = $\sqrt{27}$ = $\sqrt{9(3)}$ = $\sqrt{9}$ × $\sqrt{3}$ = 3 $\sqrt{3}$ ← exact value

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Can someone please help me with this! I'll do my best to give a lot of points for it!

Triss [41]

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8 0

3 years ago

Please help.....25 points!!!

kenny6666 [7]

Answer:

Step-by-step explanation:

We want to find the inverse of g(x). One way to do this is to switch the g(x) and x in the original equation and then solve for g(x); that will give you the inverse.

Here, $g(x)=\frac{3}{5} x-9$ . Switch the g(x) and x to become: $x=\frac{3}{5} g(x)-9$ . Now solve for g(x) by isolating it: