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Mathematics

2 answers:

igor_vitrenko [27]2 years ago

8 0

Multiply 0.25 by 2 and you get 0.50

professor190 [17]2 years ago

4 0

Answer:

I'm not sure but I got 3.694

but what I know you have to Multiply

so it will Multiply 0.25 by 2 and you get 0.50

Step-by-step explanation:

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Elanso [62]

All real numbers such that y is greater than 3/17 or y>3/17. Hope this helps!!!!

7 0

3 years ago

4y p(y) => + 5. If y = 4, then what is the value of p(y)? 9 7 13 37

Leni [432]

9514 1404 393

Answer:

C. 13

Step-by-step explanation:

Put 4 where y is in the equation and do the arithmetic.

$p(y)=\dfrac{4y}{2}+5\\\\p(4)=\dfrac{4(4)}{2}+5 = \dfrac{16}{2}+5=8+5\\\\\boxed{p(4)=13}$

3 0

3 years ago

Approximate the integral integral integral integral f(x, y) dA by dividing the rectangle R with vertices (0, 0), (4, 0), (4, 2),

amm1812

Answer:

Step-by-step explanation:

Approximate the integral $\int\int\limits_R {f(x,y)} \, dA$ by dividing the region $R$ with vertices (0,0),(4,0),(4,2) and (0,2) into eight equal squares.

Find the sum $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i$

Since all are equal squares, so $\delta A_i=1$ for every $i$

$\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=f(x_1,y_1)\delta A_1+f(x_2,y_2)\delta A_2+f(x_3,y_3)\delta A_3+f(x_4,y_4)\delta A_4+f(x_5,y_5)\delta A_5+f(x_6,y_6)\delta A_6+f(x_7,y_7)\delta A_7+f(x_8,y_8)\delta A_8\\\\=f(0.5,0.5)(1)+f(1.5,0.5)(1)+f(2.5,0.5)(1)+f(3.5,0.5)(1)+f(0.5,1.5)(1)+f(1.5,1.5)(1)+f(2.5,1.5)(1)+f(3.5,1.5)(1)\\\\=0.5+0.5+1.5+0.5+2.5+0.5+3.5+0.5+0.5+1.5+1.5+1.5+2.5+1.5+3.5+1.5\\\\=24$

Thus, $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=24$

Evaluating the iterate integral $\int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=\int\limits^4_0 {[xy+\frac{y^2}{2} ]}\limits^2_0 \, dx =\int\limits^4_0 {[2x+2]}dx\\\\=[x^2+2x]\limits^4_0=24.$