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Paha777 [63]
3 years ago
10

The sum of the lengths of any two sides of a triangle must be greater than the third side. If a triangle has one side that is 18

inches and a second side that is 3 inches less than twice the third side, what are the possible lengths for the second and third sides?
Mathematics
1 answer:
kogti [31]3 years ago
3 0

Answer: One side could be 18 and the other side will be 33.

Step-by-step explanation:

  • Side #1 = 18
  • Side #2 = 2x - 3
  • Side #3 = x

<u>One way of setting up the inequality is: Side #2 + Side #3 > Side #1</u>

<u />2x-3+x>18\\3x-3>18\\3x>18+3\\3x>21\\x>7

<u>Another way of setting up the inequality is: Side #1 + Side #3 > Side #2</u>

<u />18+x>2x-3\\18+3>2x-x\\x<u />

<u>Final way of setting up the inequality is: Side #1 + Side #2 > Side #3</u>

<u />18+2x-3>x\\15>x-2x\\15>-x\\x>-15<em />

<em>Therefore, we have the range for our value of x, which is between 7 and 21. Any possible value between works. Negative measurements are rejected. One of the sides would equal the x-value, while the other side would equal the value of 2x-3.</em>

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Answer:

a) $3480

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Step-by-step explanation:

The compound interest formula is given by:

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Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that P = 3000, r = 0.16, n = 1

So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 3000(1 + \frac{0.16}{1})^{t}

A(t) = 3000(1.16)^{t}

(a) Find the amount in the account at the end of 1 year.

This is A(1).

A(t) = 3000(1.16)^{t}

A(1) = 3000(1.16)^{1} = 3480

(b) Find the amount in the account at the end of 2 years.

This is A(2).

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3 years ago
3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k
Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

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Evaluate the integral to solve for y :

\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt

\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x

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Then the curve C has equation

\boxed{y = x^3 + 2x^2 + 2x - 2}

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\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2

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