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MArishka [77]
3 years ago
7

Select the undefined term that best defines the arrow pictured

Mathematics
2 answers:
vitfil [10]3 years ago
7 0

Answer: A line is the undefined term which best defines the arrow pictured


Step-by-step explanation:

There are three undefined terms in geometry are as follows

1) point  → has no dimensions

2) line  → has one dimension

3) plane. → has two dimensions

In the given picture, a line is the only undefined term which best fits to define the arrow pictured since arrow has only length, thus it has one dimension as a line.


olga55 [171]3 years ago
6 0
The answer is B. A point is a location, and a plane is represented by a rectangle or a parallelogram.
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What is the solution to these equations y= 2x +1 and x +2y= 27
Llana [10]

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3 years ago
The weight for crates of eggs is normally distributed with a mean weight of 34.6 pounds and a standard deviation of 2.8 pounds.
Bingel [31]

Answer:

0.5532

Step-by-step explanation:

P( 31<X<35.7)

P(X>31)= P(Z>(31-μ)/σ)

           = P(Z>(31-34.6)/2.8)

          = P(Z> -1.2857)

P(X<35.7)= P(Z<(35.7-μ)/σ)

              = P(Z<(35.7-34.6)/2.8)

              =P(Z< 0.392857)

From z-distribution table

P(Z< -1.29)= 0.09853

p(Z< 0.39) = 0.65173

P( 31<X<35.7)= P(Z<0.39)- P(Z<-1.29)

                   = 0.65173- 0.09853

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6 0
4 years ago
Read 2 more answers
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 270 day
dusya [7]

Answer:

a) 281 days.

b) 255 days

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 270, \sigma = 8

​(a) What is the minimum pregnancy length that can be in the top 8​% of pregnancy​ lengths?

100 - 8 = 92th percentile.

X when Z has a pvalue of 0.92. So X when Z = 1.405.

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 270}{8}

X - 270 = 1.405*8

X = 281

(b) What is the maximum pregnancy length that can be in the bottom 3​% of pregnancy​ lengths?

3rd percentile.

X when Z has a pvalue of 0.03. So X when Z = -1.88

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 270}{8}

X - 270 = -1.88*8

X = 255

8 0
4 years ago
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