Question

Reduce the fraction to lowest terms. Do not us- 5jk/35j2k2​

Answer 1

Answer:

$-(7jk)^{-1}$

Step-by-step explanation:

(Interpreting equation as)

$\frac{-5jk}{35k^2k^2}$

We can reduce the fraction by dividing the top and the bottom by terms they have in common.

First, lets rewrite both the numerator and denominator in terms of each other.

$\frac{-5jk}{35j^2k^2}=\frac{(-1)(5jk)}{(7jk)(5jk)}$

If you expand the fraction, you will get exactly what you start with, now this is fine.

As we can see both halves of the fraction have a common term ($5jk$), so we can divide by this - and the fraction will still be equivalent to as it was before

$\frac{-1}{7jk}$, or simplified further,

$-(7jk)^{-1}$

Answer 2

Answer:

I'm glad you asked!

Step-by-step explanation:

$(\frac{5jk}{35} j^{2} )(k^{2})$

=

$-(7jk)^{-1}$