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Sedbober [7]
3 years ago
7

Write the equation of 4x+5t=20 in slope-intercept form

Mathematics
2 answers:
AfilCa [17]3 years ago
7 0

Answer:

y=-\frac{4}{5}x +4

Step-by-step explanation:

Recall that slope-intercept form is the following form: y=mx+b, where m is the slope and b is the y-intercept.

To get an equation into slope-intercept form, we just need to solve for y.

We begin with the equation 4x+5y=20. With this, we can solve for y to get our answer.

4x+5y=20\\\\5y=-4x+20\\\\y=-\frac{4}{5}x +\frac{20}{5} \\\\y=-\frac{4}{5}x +4

Aleonysh [2.5K]3 years ago
4 0

Answer:

y=(-4/5)x+4

Step-by-step explanation:

4x+5y=20

5y=-4x+20

y=(-4/5)x+4

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Answer:

The two bottom angles of this triangle are both represented by the same variable, in this case, an x. This means, that both of the bottom angles are equal to each other.

So we have:

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4 0
3 years ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



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