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2 years ago

Write the equation of 4x+5t=20 in slope-intercept form

Mathematics

2 answers:

AfilCa [17]2 years ago

7 0

Answer:

$y=-\frac{4}{5}x +4$

Step-by-step explanation:

Recall that slope-intercept form is the following form: $y=mx+b$ , where m is the slope and b is the y-intercept.

To get an equation into slope-intercept form, we just need to solve for y.

We begin with the equation $4x+5y=20$ . With this, we can solve for y to get our answer.

$4x+5y=20\\\\5y=-4x+20\\\\y=-\frac{4}{5}x +\frac{20}{5} \\\\y=-\frac{4}{5}x +4$

Aleonysh [2.5K]2 years ago

4 0

Answer:

y=(-4/5)x+4

Step-by-step explanation:

4x+5y=20

5y=-4x+20

y=(-4/5)x+4

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Question A volleyball team sold raffle tickets to raise money for the upcoming season. They sold three different types of ticket

m_a_m_a [10]

Answer:

24 premium tickets were sold.

Step-by-step explanation:

Let :

Deluxe ticket = x

Regular tickets = x + 78

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Now we can solve the simultaneous equation using elimination method :

From (1)

y = 130 - 2x

Put y = 130 - 2x in (2)

6x + 10(130 - 2x) = 558

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2 years ago

Use the rectangle hexagon with side length 10 meters to fill in the missing information

Vlada [557]

Answer:

$A_h=150\sqrt{3}\ m^2$

Step-by-step explanation:

<u>Regular Hexagon</u>

For the explanation of the answer, please refer to the image below. Let's analyze the triangle shown inside of the hexagon. It's a right triangle with sides x,y, and z.

We know that x is half the length of the side length of the hexagon. Thus

$x=5 m$

Note that this triangle repeats itself 12 times into the shape of the hexagon. The internal angle of the triangle is one-twelfth of the complete rotation angle, i.e.

$\theta=360/12=30^o$

Now we have $\theta$ , the height of the triangle y is easily found by

$\displaystyle tan30^o=\frac{x}{y}$

Solving for y

$\displaystyle y=\frac{x}{tan30^o}=\frac{5}{ \frac{1} {\sqrt{3} }}=5\sqrt{3}$

The value of z can be found by using

$\displaystyle sin30^o=\frac{x}{z}$

$\displaystyle z=\frac{x}{sin30^o}=\frac{5}{\frac{1}{2}}=10$

The area of the triangle is

$\displaystyle A_t=\frac{xy}{2}=\frac{5\cdot 5\sqrt{3}}{2}=\frac{25\sqrt{3}}{2}$

The area of the hexagon is 12 times the area of the triangle, thus

$\displaystyle A_h=12\cdot A_t=12\cdot \frac{25\sqrt{3}}{2}=150\sqrt{3}$

$\boxed{A_h=150\sqrt{3}\ m^2}$

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