All categories

3 years ago

Just tell me how ur day was C:

Mathematics

2 answers:

ra1l [238]3 years ago

7 0

Answer:

it was awesome I convinced my brother he was adopted and got chick flea

belka [17]3 years ago

5 0

Not that good but I can't say why... I'm supposed to talk about

You might be interested in

Solve 5x - 8y = 11 for y.

disa [49]

Answer:

y = $\frac{5x-11}{8}$

Step-by-step explanation:

Given

5x - 8y = 11 ( subtract 5x from both sides )

- 8y = 11 - 5x ( multiply through by - 1 )

8y = - 11 + 5x = 5x - 11 ( divide both sides by 8 )

y = $\frac{5x-11}{8}$

3 0

3 years ago

A cyclist travels at a rate of 1.8 kilometers per minutes.how fat will the cyclist travel in 48 minutes?

WARRIOR [948]

You would multiply 1.8 × 48 to find your answer.

1.8
×48
--------
14.4
+72.0
--------
86.4

So the cyclist travels 86.4 km

4 0

3 years ago

Emma is planning a surprise party. she is considering.......

Ann [662]

Answer:

Step-by-step explanation:

what is she considering? I would need more information to complete the probolem

5 0

3 years ago

Read 2 more answers

Trigonometry please help! work need to be shown

padilas [110]

Answer:

x = 5.56

Step-by-step explanation:

Apply trigonometric function to find x

Reference angle = 46°

Hypotenuse = 8

Adjacent length = x

Apply CAH:

Cos 46 = Adj/Hyp

Cos 46 = x/8

8 × Cos 46 = x

5.55726696 = x

x = 5.56 (nearest hundredth)

7 0

3 years ago

Evaluate the integral, show all steps please!

Aloiza [94]

Answer:

$\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x=\dfrac{x}{9\sqrt{9-x^2}} +\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x$

Rewrite 9 as 3² and rewrite the 3/2 exponent as square root to the power of 3:

$\implies \displaystyle \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x$

Integration by substitution

$\boxed{\textsf{For }\sqrt{a^2-x^2} \textsf{ use the substitution }x=a \sin \theta}$

$\textsf{Let }x=3 \sin \theta$

$\begin{aligned}\implies \sqrt{3^2-x^2} & =\sqrt{3^2-(3 \sin \theta)^2}\\ & = \sqrt{9-9 \sin^2 \theta}\\ & = \sqrt{9(1-\sin^2 \theta)}\\ & = \sqrt{9 \cos^2 \theta}\\ & = 3 \cos \theta\end{aligned}$

Find the derivative of x and rewrite it so that dx is on its own:

$\implies \dfrac{\text{d}x}{\text{d}\theta}=3 \cos \theta$

$\implies \text{d}x=3 \cos \theta\:\:\text{d}\theta$

Substitute everything into the original integral:

$\begin{aligned}\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x & = \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x\\\\& = \int \dfrac{1}{\left(3 \cos \theta\right)^3}\:\:3 \cos \theta\:\:\text{d}\theta \\\\ & = \int \dfrac{1}{\left(3 \cos \theta\right)^2}\:\:\text{d}\theta \\\\ & = \int \dfrac{1}{9 \cos^2 \theta} \:\: \text{d}\theta\end{aligned}$

Take out the constant:

$\implies \displaystyle \dfrac{1}{9} \int \dfrac{1}{\cos^2 \theta}\:\:\text{d}\theta$

$\textsf{Use the trigonometric identity}: \quad\sec^2 \theta=\dfrac{1}{\cos^2 \theta}$

$\implies \displaystyle \dfrac{1}{9} \int \sec^2 \theta\:\:\text{d}\theta$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$