Answer:
<h2> 112.3 square units</h2>
Step-by-step explanation:
Find the sketch of the triangle attached.
Area of the triangle = 
Given PQ = 20, PR = 12 and ∠QPR = 68°
Area of the triangle = 1/2 * 20 * 12 * sin68°
Area of the triangle = 120sin68°
Area of the triangle = 112.26 square units
Area of the triangle ≈ 112.3 square units (to the nearest tenth of a square unit)
Answer:
69.08cm
Step-by-step explanation:
The formula for the circumference is
pi times diameter=circumference
Since we are using 3.14 and we know the diameter we can plug that in
3.14 times 22= circumference
69.08=circumference
Answer:
Step-by-step explanation:
1 in is 35 feet
1.25 * 35= 43.75 feet
Answer:
52
Step-by-step explanation:
3^3+3(3)^2-7(3)+19
27+27-21+19
54-2
52
Hope this helps
Answer:
Step-by-step explanation:
30. Given: rectangles QRST and RKST
Prove: ΔQSK is isosceles
An isosceles triangle is a triangle which has two sides and two angles to be equal.
Thus,
From rectangle QRST, the diagonals of rectangles are similar.
i.e RT ≅ QS (diagonal property)
Also, RT ≅ SK (opposite sides of rectangle RKST)
Thus,
RT ≅ QS ≅ SK
Therefore,
ΔQSK is an isosceles triangle.
31. Given: Rectangles QRST, RKST and JQST
Prove: JT ≅ KS
From rectangle QRST, the diagonals of rectangles are similar.
i.e RT ≅ QS (diagonal property)
But,
JT // QS and RT // KS
Thus,
JT ≅ QS (opposite sides of rectangle JQST)
also,
RT ≅ KS (opposite sides of rectangle RKST)
So that,
JT ≅ QS ≅ RT ≅ KS
Therefore,
JT ≅ KS
