In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
1 answer:
Answer:
The lengths of MN is 22 units, MO is 26 units and JK is 10 units
Step-by-step explanation:
<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>
In Δ MON
∵ J, K, and L are mid-points
∵ JL // MN and LK // MO
∴ L is the mid-point of ON
∴ J is the mid-point of MO
∴ K is the mid-point of MN
∵ J, L are the mid-points of MO and ON
∵ JL is opposite to MN
→ By using the rule above
∴ JL = MN
∵ JL = 11 units
∴ 11 = MN
→ Multiply both sides by 2
∴ 22 = MN
∴ MN = 22 units
∵ K, L are the mid-points of MN and ON
∵ KL is opposite to MO
→ By using the rule above
∴ KL = MO
∵ KL = 13 units
∴ 13 = MO
→ Multiply both sides by 2
∴ 26 = MO
∴ MO = 26 units
∵ J, K are the mid-points of MO and MN
∵ JK is opposite to ON
→ By using the rule above
∴ JK = ON
∵ ON =20 units
∴ JK = (20)
∴ JK = 10 units
∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units
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• zero: -4, -4/3, 7
• positive: -4 < x < -4/3 . . . or 7 < x
• negative: x < -4 . . . or -4/3 < x < 7
Step-by-step explanation:
Zeros of the function are at x=-4, -4/3, +7. These are the values that make each of the individual factors be zero. For example, x-7=0 when x=7.
The function will be negative for x-values left of an odd number of zeros. It will be positive for x-values left of an even number of zeros (including left of no zeros, which is to say right of all zeros). This is because the sign of the factor giving rise to the zero changes for x-values on either side of that zero. (This is not true for zeros with even multiplicity, as the sign does not change at those.)
