Answer:
hope this hepls u.........
Answer:
x y
-2 36
-1 6
0 1
1 1/6
2 1/36
Step-by-step explanation:
Given
![f(x) = (\frac{1}{6})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28%5Cfrac%7B1%7D%7B6%7D%29%5Ex)
Required
Complete the table
When x = -2.
Substitute -2 for
![f(-2) = (\frac{1}{6})^{-2](https://tex.z-dn.net/?f=f%28-2%29%20%3D%20%28%5Cfrac%7B1%7D%7B6%7D%29%5E%7B-2)
![f(-2) = 1/\frac{1}{36}](https://tex.z-dn.net/?f=f%28-2%29%20%3D%201%2F%5Cfrac%7B1%7D%7B36%7D)
![f(-2) = 36](https://tex.z-dn.net/?f=f%28-2%29%20%3D%2036)
When x = -1
![f(-1) = (\frac{1}{6})^{-1](https://tex.z-dn.net/?f=f%28-1%29%20%3D%20%28%5Cfrac%7B1%7D%7B6%7D%29%5E%7B-1)
![f(-1) = 1/\frac{1}{6}](https://tex.z-dn.net/?f=f%28-1%29%20%3D%201%2F%5Cfrac%7B1%7D%7B6%7D)
![f(-1) = 6](https://tex.z-dn.net/?f=f%28-1%29%20%3D%206)
When x = 0
![f(0) = \frac{1}{6}^0](https://tex.z-dn.net/?f=f%280%29%20%3D%20%5Cfrac%7B1%7D%7B6%7D%5E0)
![f(0) = 1](https://tex.z-dn.net/?f=f%280%29%20%3D%201)
When x = 1
![f(1) = \frac{1}{6}^1](https://tex.z-dn.net/?f=f%281%29%20%3D%20%5Cfrac%7B1%7D%7B6%7D%5E1)
![f(1) = \frac{1}{6}](https://tex.z-dn.net/?f=f%281%29%20%3D%20%5Cfrac%7B1%7D%7B6%7D)
When x = 2
![f(2) = \frac{1}{6}^2](https://tex.z-dn.net/?f=f%282%29%20%3D%20%5Cfrac%7B1%7D%7B6%7D%5E2)
![f(2) = \frac{1}{36}](https://tex.z-dn.net/?f=f%282%29%20%3D%20%5Cfrac%7B1%7D%7B36%7D)
Answer:
y=17
Step-by-step explanation:
cant send the pic and im not sure tho
y=mx+c
m = gradient
so find gradient
and then sub in one of the coords in x and y in the eq with the m to find c
2=3(3)+c
and then sub the 8(x coords) to find y
Answer:
A = -y^2 + 18
y = 9 + (81 - x)^(1/2) and y =9 - (18 - x) ^(1/2)
Step-by-step explanation:
Given:
P = 2 ( l + w)
x = length and y = width
P = 2 (x + y)
36/2 = x + y
x + y = 18
x = 18 - y
<u>Area:</u>
A = x * y
A = (18 - y) * y
A = 18y - y^2
Using quadratic formula (<u>solve for y</u>):
y = 9 + (81 - x)^(1/2) and y =9 - (18 - x) ^(1/2)
<em>//Not sure it's right.</em>