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Lelu [443]
2 years ago
8

In Store A the price of mayonnaise went

Mathematics
2 answers:
alukav5142 [94]2 years ago
7 0

Answer:

What is the question?

Step-by-step explanation:

beks73 [17]2 years ago
5 0

Answer:

oeenjsndn eeror

Step-by-step explanation:

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Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou
Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

x=z+136

We also know that Y weighs 117 pounds more than car Z, this can be express as:

y=z+117

Finally, we know that the total weight of all the cars is 9439, then we have:

x+y+z=9439

Hence, we have the system of the equations:

\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}

Now that we have the value of z we plug it in the first two equations to find x and y:

\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0
1 year ago
The number of acres a farmer uses for planting pumpkins will be at least 2 times the number of acres for planting corn. The diff
jeka94

Answer:

Step-by-step explanation:

A) Let x represent acres of pumpkins, and y represent acres of corn. Here are the constraints:

  x ≥ 2y . . . . . pumpkin acres are at least twice corn acres

  x - y ≤ 10 . . . . the difference in acreage will not exceed 10

  12 ≤ x ≤ 18 . . . . pumpkin acres will be between 12 and 18

  0 ≤ y . . . . . the number of corn acres is non-negative

__

B) If we assume the objective is to maximize profit, the profit function we want to maximize is ...

  P = 360x +225y

__

C) see below for a graph

__

D) The profit for an acre of pumpkins is the highest, so the farmer should maximize that acreage. The constraint on the number of acres of pumpkins comes from the requirement that it not exceed 18 acres. Then additional profit is maximized by maximizing acres of corn, which can be at most half the number of acres of pumpkins, hence 9 acres.

So profit is maximized for 18 acres of pumpkins and 9 acres of corn.

Maximum profit is $360·18 +$225·9 = $8505.

7 0
3 years ago
Jenny purchased a prepaid phone card for $30.Long distance calls cost 12 cents a minute using this card. Jenny used her card onl
Korolek [52]

Answer:

43 min

Step-by-step explanation:

subtract $24.84 from $30 and you get $5.16 and you divide that by 12 cents which then you get 43 min

4 0
3 years ago
Solve this linear system by graphing <br> x-y=6 <br> 2x=12+2y
lys-0071 [83]
You need to isolate the variables. For the first equation add x to both sides, which leaves you with y.

For the second equation, divide each side by 2 leaving you with
x= 6+y. Subtract y from each side. Subtract x from both sides. Now you have y= x + 6.

Now graph those equations.
5 0
3 years ago
Pls help me pls pls
bekas [8.4K]

Answer:

190.8

Step-by-step explanation:

Im pretty sure my math is wrong but i hope this helps

6 0
2 years ago
Read 2 more answers
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