Need math help pls:))
1 answer:
Answer:
see below
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relationships between triangle sides and trig functions. For the angle of interest, the diagram shows values for the Opposite side (12) and the Adjacent side (16.5). The mnemonic tells you that these are related to the Tangent of the angle:
Tan = Opposite/Adjacent
tan(θ) = (12/16.5)
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Write the vertex form of the equation and find the necessary coefficient to make it work.
.. y = a*(x +3)^2 -2
.. = ax^2 +6ax +9a -2
You require the y-intercept to be 7. So, for x=0, you have
.. 9a -2 = 7
.. 9a = 9
.. a = 1
The equation you seek is
.. y = x^2 +6x +7
.. y = a*(x +3)^2 -2
.. = ax^2 +6ax +9a -2
You require the y-intercept to be 7. So, for x=0, you have
.. 9a -2 = 7
.. 9a = 9
.. a = 1
The equation you seek is
.. y = x^2 +6x +7