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Pepsi [2]
3 years ago
15

The lines p and q intersect at point O. What is the value of x? Enter your answer in the box. x =

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

x = 16

Step-by-step explanation:

The two angles are vertical angles, which means they are equal

3x-3 = 2x+13

Subtract 2x from each side

3x-3-2x =2x-2x+13

x-3 =13

Add 3 to each side

x-3+3 =13+3

x = 16

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Calculate the average rate of change from x = 0 to x = 3. Show work please
AURORKA [14]
Rate=\frac{f(b)-f(a)}{b-a}=\frac{f(3)-f(0)}{3-0}=\frac{3-(-4)}{3}=\frac{7}{3}
3 0
3 years ago
Simplify the expression below -3(10x + 4y) + 6(6x − 2y)
iren [92.7K]

Answer:

6x - 24y

Explanation:

Expand -3(10x + 4y): -30x - 12y

= \bold{-30x-12y+6\left(6x-2y\right)}

Simplify \bold{-30x-12y+6\left(6x-2y\right): \ 6x-24y}

= 6x - 24y

Mordancy.

3 0
3 years ago
Read 2 more answers
What is the side length of a 36 inch cube
Vladimir [108]

The side length is 3 inches

<h3>What is the perimeter of a cube?</h3>

The formula for perimeter of a cube is given as:

Perimeter = 12 × side length

We have that;

  • Perimeter = 36 inches
  • Side length be x

Substitute into the formula

12x = 36

Divide both sides by 12

12x/12 = 36 / 12

x = 3 inches

The side length is x and equal to 3 inches.

Hence, the side length is 3 inches

Learn more about a cube here:

brainly.com/question/1972490

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8 0
2 years ago
From a deck of five cards numbered 2, 4, 6, 8, and 10, respectively, a card is drawn at random and replaced. this is done three
Serga [27]

Since the sum of the numbers on the three draws is 12, if we want the card numbered 2 to be drawn exactly two times, the third card can only be numbered 8. In fact, 2+2+8 = 12, and there are no other possibilities, unless you consider the various permutations of the terms.

So, we have three favourable cases: we can draw 2,2,8, or 2,8,2, or 8,2,2. This are the only three cases where the card numbered 2 is drawn exactly two times, and the sum of the number on the three draws is 12.

Now, the question is: we have three favourable cases over how many? Well, we have 5 possible outcomes with each draws, and the three draws are identical, because we replace the card we draw every time.

So, we have 5 possible outcomes for the first draw, 5 for the second and 5 for the third. This leads to a total of 5 \times 5 \times 5 = 5^3 = 125 possible triplets.

Once we know the "good" cases and the total number of possible cases, the probability is simply computed as

P = \cfrac{\text{number of favourable cases}}{\text{number of all possible cases}} = \cfrac{3}{125}

3 0
3 years ago
Find the missing x- and y-values and Pythagorean triples can be generated using the identity given. Write the triple in parenthe
ddd [48]

The complete question is:

Find the missing x- and y-values and Pythagorean triples using the identity given:

(x² - y²)² + (2xy)² = (x² + y²)²

X Value: 4

Y Value: 3

Pythagorean Triples: ?

X Value: 5

Y Value: ?

Pythagorean Triples: (9,40,41)

X Value: ?

Y Value: 3

Pythagorean Triples: (27,36,45)

X Value: 7

Y Value: 5

Pythagorean Triples: ?

Step-by-step explanation:

Pythagorean triples are three numbers p, q, r, that satisfy Pythagoras' theorem.

That is, they are numbers such that

r² = p² + q².

Given the identity

(x² - y²)² + (2xy)² = (x² + y²)²

We can say tha

p = x² - y²

q = 2xy

r = x² + y²

Now, let us use this to solve the given problems.

X Value: 4

Y Value: 3

p = 4² - 3² = 7

q = 2×3×4 = 24

r = 3² + 4² = 25

Pythagorean Triples: (7,24,25)

X Value: 5

Y Value: ? = (4)

q = 2xy = 40

2×5×y = 40

y = 40/10 = 4

Pythagorean Triples: (9,40,41)

X Value: ? = (6)

Y Value: 3

2xy = q = 36

2×3×x = 36

x = 36/6 = 6

Pythagorean Triples: (27,36,45)

X Value: 7

Y Value: 5

p = 7² - 5² = 24

q = 2×7×5 = 70

r = 7² + 5² = 74

Pythagorean Triples: ? = (24,70,74)

8 0
3 years ago
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