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Ivan
3 years ago
6

A triangle has the coordinates

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , thus

A(4, - 1 ) → A'(- 4, - 1 )

B(3, - 3 ) → B'(- 3, - 3 )

C(0, 2 ) → C'(0, 2 )

You might be interested in
Scores on an exam follow an approximately normal distribution with a mean of 76. 4 and a standard deviation of 6. 1 points. What
crimeas [40]

If scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points, then the minimum score you would need to be in the top 2% is equal to 88.929.

A problem of this type in mathematics can be characterized as a normal distribution problem. We can use the z-score to solve it by using the formula;

Z = x - μ / σ

In this formula the standard score is represented by Z, the observed value is represented by x, the mean is represented by μ, and the standard deviation is represented by σ.

The p-value can be used to determine the z-score with the help of a standard table.

As we have to find the minimum score to be in the top 2%, p-value = 0.02

The z-score that is found to correspond with this p-value of 0.02 in the standard table is 2.054

Therefore,

2.054 = x - 76.4 ÷ 6.1

2.054 × 6.1 = x - 76.4

12.529 = x - 76.4

12.529 + 76.4 = x

x = 88.929

Hence 88.929 is calculated to be the lowest score required to be in the top 2%.

To learn more about normal distribution, click here:

brainly.com/question/4079902

#SPJ4

5 0
1 year ago
The length of a bridge is 190 m. The length of each of Robert's paces is 80 cm.
ohaa [14]

Answer:

Step-by-step explanation:

Length of the bridge = 190 m = 190*100 = 19000 cm    {100cm = 1m}

Length of each pace of Robert = 80 cm

Minimum number of full paces = 19000/80

=  237.5

= 238   {because full paces}

5 0
3 years ago
Read 2 more answers
Which expression is equivalent to the given expression? −(12y+14) A:−14(1+2y) B:14(2y−1) C:−2(14y−18) D:2(18−14y)
Nuetrik [128]

- 1/4 ( 1 + 2y) was the answer i got

6 0
3 years ago
Read 2 more answers
1948 Olympics
mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

8 0
4 years ago
Please I need help!!!
Natalija [7]

Answer:

58

Step-by-step explanation:

-14 + x = 44

x = 44 + 14

x = 58

3 0
3 years ago
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