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1 year ago

Find the circumference, 18 ft

Mathematics

1 answer:

Marysya12 [62]1 year ago

5 0

Answer:

56.549 feet

Step-by-step explanation:

Diameter. ft in m

18′0″ 56.55. 678.6 17.24

18′1″ 56.81.

18′2″ 57.07. 684.9

18′3″ 57.33. 688.0

18′4″ 57.60. 691.2

18′5″ 57.86. 694.3 17.64

18′6″ 58.12. 697.4 17.71

18′7″ 58.38 700.6 17.79

18′8″ 58.64 703.7 17.87

18′9″ 58.90. 706.9 17.95

18′10″ 59.17. 710.0 18.03

18′11″ 59.43. 713.1 18.11

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2 years ago

The excursion boat on the river takes 2½ hours to make the trip to a point 12 miles upstream and to return. If the rate at which

Orlov [11]

Answer:

2 mph

Step-by-step explanation:

time = distance / speed

Let c represent the rate of the current. Then the upstream rate of the boat relative to the shore is (5c -c) = 4c, and the upstream time is ...

... 12/(4c) = 3/c.

Likewise, the downstream rate is (5c +c) = 6c, and the downstream time is ...

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2 years ago

The perimeter of a pentagon (5 sides) is 10.5 centimeters. The sides are x,x,x,x and 1.7 cm. What is the value of x

Drupady [299]

Answer:

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Step-by-step explanation:

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2 years ago

Select all that apply.

Mila [183]

First we need to have same units before comparing them. That is, either both of them are in cm or both of them are in mm. So if we need to convert 12.5 cm to mm, we know that 1 cm =10 mm. So we have to find out how many mm are in 12.5 cm. And let 12.5 cm =x mm. So to find the value of x , we set a proportion and solve for x. That is

$\frac{1cm}{10mm}=\frac{12.5cm}{x mm}$

The units cancel out and we do cross multiplication. That is

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2 years ago

What is the equation of the line that passes through the points (-1, 1.5) and (0.5, 0.5)

Step2247 [10]

The slope-point formula:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have:

$(-1,\ 1.5)\to x_1=-1,\ y_1=1.5\\(0.5,\ 0.5)\to x_2=0.5,\ y_2=0.5$

Substitute:

$m=\dfrac{0.5-1.5}{0.5-(-1)}=\dfrac{-1}{1.5}=-\dfrac{1}{\frac{3}{2}}=-\dfrac{2}{3}\\\\y-1.5=-\dfrac{2}{3}(x-(-1))\\\\y-1.5=-\dfrac{2}{3}x-\dfrac{2}{3}\\\\y-\dfrac{3}{2}=-\dfrac{2}{3}x-\dfrac{2}{3}\ \ \ |+\dfrac{3}{2}\\\\y=-\dfrac{2}{3}x-\dfrac{2}{3}+\dfrac{3}{2}\\\\y=-\dfrac{2}{3}x-\dfrac{2\cdot2}{3\cdot2}+\dfrac{3\cdot3}{2\cdot3}\\\\y=-\dfrac{2}{3}x-\dfrac{4}{6}+\dfrac{9}{6}\\\\y=-\dfrac{2}{3}x+\dfrac{5}{6}$

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2 years ago