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ANEK [815]
3 years ago
9

Consider the following simplified algebraic expression. 10 x squared y + 6 x squared minus 7 y squared minus 6 Which could be th

e original expression? 8 x squared y + 7 x squared minus 5 y squared + 3 x minus 2 + 2 x squared y minus x squared minus 2 y squared + 3 x minus 4 8 x squared y + 7 x squared minus 5 y squared + 3 x minus 2 + 2 x squared y minus x squared minus 2 y squared minus 3 x minus 4 8 x squared y + 7 x squared minus 5 y squared + 3 x + 2 + 2 x squared y minus x squared minus 2 y squared minus 3 x minus 4 8 x squared y + 7 x squared minus 5 y squared + 3 x minus 2 minus 2 x squared y minus x squared minus 2 y squared minus 3 x minus 4
Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
6 0
2 y squared minus 65 minus 38
Dmitrij [34]3 years ago
5 0

2 y squared minus 3 x minus 4 8 x squared

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PLZ HELP!
gizmo_the_mogwai [7]
Your answer would be B. William will pay $392.30 with his, and at the store he'll pay $402.15. :)
4 0
3 years ago
Please help me please
Dmitry [639]

Answer:c because the angle to the left and right are equal

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
EXERC
eimsori [14]

Answer:551.3212cm³

Step-by-step explanation:

Find the image attached

The volume is made up of a cone, cylinder and a hemisphere

Volume of the shape = Volume of cone + volume of cylinder + volume of hemisphere

Get the volume of the cone;

Volume of a cone Vc = 1/3πr²h

r is the base radius = 3.5cm

Height = 10cm

Vc = 1/3π(3.5)²(6)

Vc = 1/3π(12.25)(6)

Vc = 12.25 * 2π

Vc = 24.5π cm³

Get the volume of the cylinder;

Vcy = πr²h

r = 3.5cm

h = 10cm

Vcy = π(3.5)²(10)

Vcy = π(12.25)(10)

Vcy = π(122.5)

Vcy = 122.5π cm³

Get rhe volume of the hemisphere;

Volume of hemisphere = 2/3 πr³

r = 3.5cm

Vh =  2/3 π(3.5)³

Vh = 2/3π(42.875)

Vh = 28.58π cm³

Volume of the shape = VC + Vcy + Vh

Volume of the shape = 24.5π+122.5π+28.58π

Volume of the shape = 175.58π

<em>Volume of the shape = 551.3212cm³</em>

7 0
3 years ago
NEED HELP FAST!!!
mina [271]
Remember

we can do anything to an equation as long as we do it to both sides

try to isolate the variable

you have 2 types
x+b=c
x/b=c

fior the first type, minus b from both sides to get
x=c-b

for the second, multiply both sides by b to get rid of the fraction to get
x=cb

also remember that -x times -1=x



b.add 25 to both sides
-a=20
multiply -1
a=-20


c.
-t/8=-4
multiply both sides by 8
-t=-32
mutiply -1
t=32

d. -n/-5=-30
mulitply both sides by -5
-n=150
multiply both sides by -1
n=-150

e. multiply both sides by 12
-l=144
multiply b y-1
l=-144
4 0
3 years ago
Read 2 more answers
Two sets of equatic expressions are shown below in various forms: Line 1: x2 + 3x + 2 (x + 1)(x + 2) (x + 1.5)2 − 0.25 Line 2: x
kherson [118]

Answer:  The correct line is

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Step-by-step explanation:  We are given the following two sets of quadratic expressions in various forms:

\textup{Line 1: }x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25,\\\\\textup{Line 2 :}x^2+5x+6=(x+2)(x+3)=(x+2.5)^2+6.25.

We are to select one of the lines from above that represent three equivalent expressions.

We can see that there are three different forms of a quadratic expression in each of the lines:

First one is the simplified form, second is the factorised form and third one is the vertex form.

So, to check which line is correct, we need to calculate the factorised form and the vertex form from the simplified form.

We have

\textup{Line 1: }\\\\x^2+3x+2\\\\=x^2+2x+x+2\\\\=x(x+2)+1(x+2)\\\\=(x+1)(x+2),

and

x^2+3x+2\\\\=x^2+2\times x\times 1.5+(1.5)^2-(1.5)^2+2\\\\=(x+1.5)^2-2.25+2\\\\=(x+1.5)^2-0.25.

So,

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Thus, Line 1 contains three equivalent expressions.

Now,

\textup{Line 2: }\\\\x^2+5x+6\\\\=x^2+3x+2x+6\\\\=x(x+3)+2(x+3)\\\\=(x+2)(x+3),

and

x^2+5x+6\\\\=x^2+2\times x\times 2.5+(2.5)^2-(2.5)^2+6\\\\=(x+2.5)^2-6.25+6\\\\=(x+2.5)^2-0.25\neq (x+2.5)^2+6.25.

So,

\textup{Line 2 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2+6.25.

Thus, Line 2 does not contain three equivalent expressions.

Hence, Line 1 is correct.

7 0
3 years ago
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