Yes, by 0.001. Thank me later.
Answer:
n=-2
Step-by-step explanation:
1−(2n+9)=4(1−2)
1+−1(2n+9)=4(1−2)
1+−1(2n)+(−1)(9)=4(1−2)
1+−2n+−9=4(1−2)
1+−2n+−9=−4
(−2n)+(1+−9)=−4
−2n+−8=−4
−2n−8=−4
−2n−8+8=−4+8
−2n=4
Divide both sides by -2
-2n/2=4/-2
n=-2
1/6
Step-by-step explanation:
- According to the question, the right combination of 2 wires cut (out of the 4 wires ) will defuse the bomb. To find all the possible combinations we using the following formulae;
nCr = n! / r! * (n - r)!
⁴₂C = 4! / 2! * (4-2)!
⁴₂C = 24 / 2 * 2
⁴₂C = 6
- There are a possible 6 combinations
- Therefore for probability of cutting the right combination of 2 wires is 1/6
Learn More:
To learn more about combinations check out;
brainly.com/question/3374511
brainly.com/question/3901018
#LearnWithBrainly
Answer:
-6 and 7
Step-by-step explanation:
-6 * 7 = -42 and -6 + 7 = 1, so they are factors and have a sum of 1.
6 is c, i'm not entirely sure about 7
