Answer:
129.78m
Explanation:
The following data were obtained from the question:
θ = 16.9°
U = 48.3m/s
g = 10m/s2
R =?
R = U^2 Sin2θ / g
R = (48.3)^2 Sin33. 8/ 10
R = 129.78m
Explanation:
kinetic energy is energy that it possesses due to its motion.
To solve this problem it is necessary to apply the concepts related to the electric field according to the definition of Coulomb's law.
The electric field is defined mathematically as a vector field that associates to each point in space the (electrostatic or Coulomb) force per unit of charge exerted on an infinitesimal positive test charge at rest at that point.
Mathematically this can be described as:
Where,
permittivity of free space
r = Distance
q = Charge
E = Electric Field
Our values are given as,
Replacing we have,
Therefore the amoun of charge on the outer surface of the larger shell is 
Weight = (mass) x (gravity).
It always acts downward.
On Earth, the acceleration of gravity is 9.807 m/s².
On the Moon, the acceleration of gravity is 1.623 m/s².
On Earth, the rocket's weight is (0.8kg) x (9.8 m/s²) = 7.84 newtons
On the Moon, the rocket's weight is (0.8kg) x (1.62 m/s²) = 1.3 newtons
The force of the rocket engine acts upward.
Its magnitude is 12 newtons. (From the burning chemicals.
Doesn't depend on local gravity. Same force everywhere.)
Now we have all the data we need to mash together and calculate the
answers to the question. You might choose a different method, but the
machine that I have selected to do the mashing with is Newton's 2nd law
of motion:
Net Force = (mass) x (acceleration).
Since the question is asking for acceleration, let's first solve Newton's law
for it. Divide each side by (mass) and we have
Acceleration = (net force) / (mass) .
On Earth, the forces on the rocket are
(weight of 7.84 N down) + (blast of 12 N up) = 4.16 newtons UP (net)
Acceleration = (4.16 newtons UP) / (0.8 kg) = 5.2 m/s² UP .
On the moon, the forces on the rocket are
(weight of 1.3 N down) + (blast of 12 N up) = 10.7 newtons UP (net)
Acceleration = (10.7 newtons UP) / (0.8 kg) = 13.375 m/s² UP
Answer:
The copper wire stretches 6.25 cm and the steel wire stretches 3.75 cm.
Explanation:
Young's modulus is defined as:
E = stress / strain
E = (F / A) / (dL / L)
E = (F L) / (A dL)
Solving for dL:
dL = (F L) / (A E)
The wires have the same force, length, and cross-sectional area. So:
dL₁ + dL₂ = (FL/A) (1/E₁ + 1/E₂)
Given that dL₁ + dL₂ = 0.10 m, E₁ = 20×10¹⁰ N/m², and E₂ = 12×10¹⁰ N/m²:
0.10 = (FL/A) (1/(20×10¹⁰) + 1/(12×10¹⁰))
FL/A = 0.75×10¹⁰ N/m
Solving for dL₁ and dL₂:
dL₁ = (FL/A) / E₁
dL₁ = (0.75×10¹⁰ N/m) / (20×10¹⁰ N/m²)
dL₁ = 0.0375 m
dL₂ = (FL/A) / E₂
dL₂ = (0.75×10¹⁰ N/m) / (12×10¹⁰ N/m²)
dL₂ = 0.0625 m
The copper wire stretches 6.25 cm and the steel wire stretches 3.75 cm.
