What is the mass of a cow moving at a velocity of 0.5 m/s with 25J of kinetic energy? Show work
2 answers:
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Answer: please see attached work.
Explanation: please see attached work. Assuming 500 sheets of paper = 20 lb. (typicical value).
Answer:
The force is
Explanation:
From the question we are told that
The mass of the block is
The coefficient of static friction is
The coefficient of kinetic friction is
The normal force acting on the block is
substituting values
Given that the force we are to find is the force required to get the block to start moving then the force acting against this force is the static frictional force which is mathematically evaluated as
substituting values
Now for this block to move the force require is equal to i.e
=>
Explanation:
'What is the magnitude of the force needed to stop the horses and bring the box into equilibrium?' ≈42N; according to the vectors rules.
'Where would you locate the rope to apply the force?' - in point D.
PS. zoom out the attached picture.
