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3 years ago

What is the mass of a cow moving at a velocity of 0.5 m/s with 25J of kinetic energy? Show work

Physics

2 answers:

Karo-lina-s [1.5K]3 years ago

5 0

Answer:

200 kg

Explanation:

Free_Kalibri [48]3 years ago

3 0

Answer:

m= 50

Explanation:

m=f/a this is the formula for mass

m= 25/0.5 you substitute the numbers with their variables they you divide them to get the mass

m= 50

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OLEGan [10]

Answer:

10 ohm

Explanation:

Since the resistors are arranged in series, their total resistance is their sum.

Hence, Total R = 2+3+5 = <u>10 ohm</u>

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3 years ago

You toss a rock of mass mm vertically upward. Air resistance can be neglected. The rock reaches a maximum height hh above your h

skad [1K]

Answer:

The speed of the rock when it is at height h/4 is $\dfrac{\sqrt{3gh} }{2}$ .

Explanation:

At maximum height the final velocity of the rock is equal to 0. Let u is the initial velocity of the rock. Using the conservation of energy to find it as :

$u^2=2gh$ .......(1)

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$v'^2=u^2+2as$

here a = -g and s = h/4

$v'^2=u^2-2g\times \dfrac{h}{4}$

Using equation (1) :

$v'^2=(2gh)-2g\times \dfrac{h}{4}\\\\v'^2=\dfrac{3gh}{4}\\\\v'=\dfrac{\sqrt{3gh} }{2}$

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A large crate is suspended from the end of a vertical rope. Is the tension in the rope greater when the crate is at rest or when

choli [55]

Answer:

Part a)

the tension force is equal to the weight of the crate

Part b)

tension force is more than the weight of the crate while accelerating upwards

tension force is less than the weight of crate if it is accelerating downwards

Explanation:

Part a)

When large crate is suspended at rest or moving with uniform speed then it is given as

$F_t - mg = ma$

here since speed is constant or it is at rest

so we will have

$a = 0$

$F_t = mg$

so the tension force is equal to the weight of the crate

Part b)

Now let say the crate is accelerating upwards

now we can say

$F_t - mg = ma$

$F_t = mg + ma$

so tension force is more than the weight of the crate

Now if the crate is accelerating downwards

$F_t - mg = -ma$

$F_t = mg - ma$

so tension force is less than the weight of crate if it is accelerating downwards

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3 years ago