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neonofarm [45]
3 years ago
12

In which part of the ear is the sound wave converted into an electrical impulse?

Physics
2 answers:
lilavasa [31]3 years ago
9 0

The ear is divided into three parts that are: The outer ear, the inner ear and the middle ear.

The outer ear and the middle ear collects and transmits the sound waves but it is the inner ear which converts sound waves into an electrical impulse as the inner ear consists of cochlea which is a snail shaped organ, lined with delicate cilia which is responsible for converting the sound waves to electrical impulse.

When the vibration is received from the middle ear, the vibrations of these cilia is converted to nerve impulses which are transmitted by auditory nerve to the brain for the interpretation as the sound.

wel3 years ago
7 0
That's in the cochlea, in the inner ear.
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3 years ago
20.0 moles, 1840 g, of a nonvolatile solute, C 3H 8O 3 is added to a flask with an unknown amount of water and stirred. The solu
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Answer:

0.144 kg of water

Explanation:

From Raoult's law,

Mole fraction of solvent = vapor pressure of solution ÷ vapor pressure of solvent = 423 mmHg ÷ 528.8 mmHg = 0.8

Let the moles of solvent (water) be y

Moles of solute (C3H8O3) = 2 mole

Total moles of solution = moles of solvent + moles of solute = (y + 2) mol

Mole fraction of solvent = moles of solvent/total moles of solution

0.8 = y/(y + 2)

y = 0.8(y + 2)

y = 0.8y + 1.6

y - 0.8y = 1.6

0.2y = 1.6

y = 1.6/0.2 = 8

Moles of solvent (water) = 8 mol

Mass of water = moles of water × MW = 8 mol × 18 g/mol = 144 g = 144/1000 = 0.144 kg

7 0
3 years ago
A drone flies 8 m/s due East with respects to the wind. The wind is blowing 6 m/s due North with respects to the ground. What is
vekshin1

Answer:

B. 10m/s

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If a drone flies 8 m/s due East with respects to the wind and the wind is blowing 6 m/s due North, the speed of the drone with respect to the ground is its displacement.

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8 0
3 years ago
5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
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306 m/s

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m1v1 + m2v2 = (m1+m2)vf

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v2 is the targets velocity, and since it was stationary, its velocity is zero

vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s

plugging in, we get

(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)

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In unit-vector notation, what is the torque about the origin on a particle located at coordinates (0 m, −3.0 m, 2.0 m) due to fo
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Answer:

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