Answer:
Linear momentum is mass multiplied by velocity, so it follows that angular momentum is the moment of inertia, measured in kilogram meters squared, multiplied by angular velocity, measured in radians per second. Radians are just an alternative to degrees.
Answer:
Explanation:
y = 16 sinπx/15 cos(96πt)
When t = 0
y = 16 sinπx/15
here πx/15 is phase of the point at x
if x = 13
Phase = 13π/15
if x = 16
Phase = 16π/15
Phase difference
= 16π/15 - 13π/15
= 3π/15
= π/5 radian .
Answer:
6400 m
Explanation:
You need to use the bulk modulus, K:
K = ρ dP/dρ
where ρ is density and P is pressure
Since ρ is changing by very little, we can say:
K ≈ ρ ΔP/Δρ
Therefore, solving for ΔP:
ΔP = K Δρ / ρ
We can calculate K from Young's modulus (E) and Poisson's ratio (ν):
K = E / (3 (1 - 2ν))
Substituting:
ΔP = E / (3 (1 - 2ν)) (Δρ / ρ)
Before compression:
ρ = m / V
After compression:
ρ+Δρ = m / (V - 0.001 V)
ρ+Δρ = m / (0.999 V)
ρ+Δρ = ρ / 0.999
1 + (Δρ/ρ) = 1 / 0.999
Δρ/ρ = (1 / 0.999) - 1
Δρ/ρ = 0.001 / 0.999
Given:
E = 69 GPa = 69×10⁹ Pa
ν = 0.32
ΔP = 69×10⁹ Pa / (3 (1 - 2×0.32)) (0.001/0.999)
ΔP = 64.0×10⁶ Pa
If we assume seawater density is constant at 1027 kg/m³, then:
ρgh = P
(1027 kg/m³) (9.81 m/s²) h = 64.0×10⁶ Pa
h = 6350 m
Rounded to two sig-figs, the ocean depth at which the sphere's volume is reduced by 0.10% is approximately 6400 m.
19.2 meters/second^2 would be the correct answer.
Try multiplying 3.2 meters/second^2 by 6 and you will receive the answer provided above. If you have any further questions, let me know!
The brakes do
<em>W</em> = ∆<em>K</em> = 0 - 1/2 (1800 kg) (40 m/s)² = -1.44 MJ (megaJoules)
of work on the car to stop it. They apply a negative force since the braking opposes the car's forward displacement, so the car stops over a distance <em>x</em> such that
<em>W</em> = (-24.6 kN) <em>x</em> ==> <em>x</em> ≈ 58.5 m
= speed of sound in air = 343 m/s
= speed of sound in the rod =
= times interval between the hearing the sound twice = 0.12 s
= length of the rod
= time taken by the sound to travel through the rod
= time taken by the sound to travel to through air to the same point =