Ask question

Ask question

All categories

liberstina [14]

2 years ago

10

A skyscraper is a rectangular prism with a height of 398 meters. The bases are squares with sides that are 62 meters. What is th

e surface area of the skyscraper?

2 answers:

nataly862011 [7]2 years ago

5 0

Answer:

106,392 meters squared.

Step-by-step explanation:

Surface area of a rectangular prism or cuboid is given by:

SA = 2 (lw + wh + lh)

where:

· l is the length of the cuboid.

· w is the width of the cuboid.

· h is the length of the cuboid.

Here we have h = 398 m, l = w = 62 m because this is a square base.

So we get:

SA = 2 ( 398 · 62 + 62² + 398 · 62)

= 2 (24676 + 3844 + 24676)

= 2 · 53196

= 106392 m²

Delvig [45]2 years ago

3 0

98766

Mark brainliest please

Hope this helps you

You might be interested in

PLEASE HELP 9 THROUGH<br> 12 ILL MARK BRAINLEST

UNO [17]

9. -7/12
10. -2.75
11. 1.844
12. 4.539

5 0

2 years ago

Read 2 more answers

Consider the statements below. Which are propositions? Mark all that apply.

allochka39001 [22]

The following statements are considered to be propositions:

2 + 2 = 7

There are more men than women at BYU-Idaho.

2 + 2 = 4

Ron hates spiders.

<h3>What is deductive reasoning?</h3>

Deductive reasoning can be defined as a type of logical reasoning that typically involves drawing conclusions based on a given set of rules and conditions or from one or more premises (factual statements) that are assumed to be generally (universally) true.

<h3>What is a proposition?</h3>

A proposition can be defined as a type of statement (assertion) that is typically used to express an opinion or a judgement, with either a true or false answer.

This ultimately implies that, a proposition refers to a type of statement (assertion) that is either a true or false.

In this context, we can infer and logically deduce that the following statements are considered to be propositions:

2 + 2 = 7

There are more men than women at BYU-Idaho.

2 + 2 = 4

Ron hates spiders.

Read more on propositions here: brainly.com/question/24158168

#SPJ1

5 0

1 year ago

Please help Evaluate 5 - (3/2) to the 3 power A.) 13/8 B.) 9.5 C.) 18.5 D.) 2197/8

Alex777 [14]

Answer: THE ANSWER IS A

Step-by-step explanation:

5-(3/2)^3

=13/8

im a math god

4 0

3 years ago

Determine whether the following series converge or diverge

Mars2501 [29]

An alternating series $\sum\limits_n(-1)^na_n$ converges if $|(-1)^na_n|=|a_n|$ is monotonic and $a_n\to0$ as $n\to\infty$ . Here $a_n=\dfrac1{\ln(n+1)}$ .

Let $f(x)=\ln(x+1)$ . Then $f'(x)=\dfrac1{x+1}$ , which is positive for all $x>-1$ , so $\ln(x+1)$ is monotonically increasing for $x>-1$ . This would mean $\dfrac1{\ln(x+1)}$ must be a monotonically decreasing sequence over the same interval, and so must $a_n$ .

Because $a_n$ is monotonically increasing, but will still always be positive, it follows that $a_n\to0$ as $n\to\infty$ .

So, $\sum\limits_n(-1)^na_n$ converges.

5 0

2 years ago

A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation $A=45e^{-0.05t}$ .

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate $A=15$ and solve for t as:

$15=45e^{-0.05t}$

$\frac{15}{45}=\frac{45e^{-0.05t}}{45}$

$\frac{1}{3}=e^{-0.05t}$

Now we will switch sides:

$e^{-0.05t}=\frac{1}{3}$

Let us take natural log on both sides of equation.

$\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})$

Using natural log property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})$

$-0.05t\cdot (1)=\text{ln}(\frac{1}{3})$

$-0.05t=\text{ln}(\frac{1}{3})$

$t=\frac{\text{ln}(\frac{1}{3})}{-0.05}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}$

$t=-\text{ln}(\frac{1}{3})\cdot 20$

$t=-(\text{ln}(1)-\text{ln}(3))\cdot 20$

$t=-(0-\text{ln}(3))\cdot 20$

$t=20\text{ln}(3)$

Therefore, it will take $20\text{ln}(3)$ years for area of the glacier to decrease to 15 square kilo-meters.

6 0

2 years ago