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liberstina [14]
3 years ago
10

A skyscraper is a rectangular prism with a height of 398 meters. The bases are squares with sides that are 62 meters. What is th

e surface area of the skyscraper?
Mathematics
2 answers:
nataly862011 [7]3 years ago
5 0

Answer:

106,392 meters squared.

Step-by-step explanation:

Surface area of a rectangular prism or cuboid is given by:

SA = 2 (lw + wh + lh)

where:

· l is the length of the cuboid.

· w is the width of the cuboid.

· h is the length of the cuboid.

Here we have h = 398 m, l = w = 62 m because this is a square base.

So we get:

SA = 2 ( 398 · 62 + 62² + 398 · 62)

= 2 (24676 + 3844 + 24676)

= 2 · 53196

= 106392 m²

Delvig [45]3 years ago
3 0
98766


Mark brainliest please


Hope this helps you
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STEP - BY - STEP EXPLANATION

What to find?

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\tan 2x=\frac{2\tan x}{1-\tan ^2x}=\frac{2(\frac{2}{3})}{1-(\frac{2}{3})^2}=\frac{\frac{4}{3}}{1-\frac{4}{9}}=\frac{\frac{4}{3}}{\frac{9-4}{9}}=\frac{\frac{4}{3}}{\frac{5}{9}}=\frac{4}{3}\times\frac{9}{5}=\frac{4}{1}\times\frac{3}{5}=\frac{12}{5}

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