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2 years ago

Could somebody help me on this please

Mathematics

1 answer:

artcher [175]2 years ago

8 0

Answer:

right angle:-a Pythagorean theorem only works if the triangle is a right angle.

leg:- the two legs of a triangle are needed to complete the equation a²+b²=c²

hypotenuse:- too is needed to complete the equation too.

square root:- is used to simplify the equation at the end.

it was simplified by putting 169=x² in a square root.

Step-by-step explanation:

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Find the perimeter of the quadrilateral that has vertices at (8,13), (5,-18), (-6,-6), and (-2,-5).

kodGreya [7K]

Answer:

72.14 units

Step-by-step explanation:

Let A(8,13), B(5,-18),C(-6,-6) and D(-2,-5)

Apply the distance formula as;

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Finding the lengths of the segments

For AB

$AB=\sqrt{(5-8)^2+(-18-13)^2} =\sqrt{(-3^2)+(-31^2)} =\sqrt{970} =31.14$

For BC

$BC=\sqrt{(-6-5)^2+(-6--18)^2} =\sqrt{(-11^2)+12^2} =\sqrt{265} =16.28$

For CD

$CD=\sqrt{(-2--6)^2+(-5--6)^2} =\sqrt{4^2+1^2} =\sqrt{16+1} =\sqrt{17} =4.12$

For DA

$DA=\sqrt{(8--2)^2+(13--5)^2} =\sqrt{10^2+18^2} =\sqrt{424} =20.6$

Finding the perimeter will be;

31.14+16.28+4.12+20.6=72.14 units

3 0

2 years ago

What is the value of C in the matrix equation below?

lara [203]

Given:

The matrix equation is:

$\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}$

To find:

The value of matrix C.

Solution:

Let $A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}$ . Then the given equation can be rewritten as

$A-C=B$

$-C=B-A$

$C=-(B-A)$

$C=A-B$

On substituting the values of the matrices, we get

$C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}$

$C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}$

$C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}$

$C=\begin{bmatrix}-4&2&-7\end{bmatrix}$

Therefore, the correct option is C.

6 0

2 years ago

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Which of the following statements are never true? Select all that apply. Three points are coplanar Two planes meet in exactly on

statuscvo [17]

Answer: Two planes meet in exactly one point

Two lines meet at exactly two points

Step-by-step explanation:

From the given statements there are two statements which are never true :-

1) Two planes meet in exactly one point .

Since when two line meets , they either meet at one point or infinite points (coincidence) , thus its impossible that they will meet at exactly two points.

2) Two lines meet at exactly two points

Since when two planes meet , the intersection of two plane always make a line not a point. Thus its impossible.

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3 years ago

Ok but why are so many people doing face reveals on this app?!? Anyways…

NeTakaya

Answer:

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Step-by-step explanation: lol

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What is the slope-intercept form of this equation?

quester [9]

8X+6Y=12

Here's how you solve it:

Just isolate y by itself to get y-intercept form.
This is the formula: Y=MX+B

M is the slope or the number next to X in the original problem.

First:
6Y=-8X+12

Next:
divided everything by 6

Y=-4/3+2

I think the answer is A!

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2 years ago

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