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2 years ago

I need help with this geometry assignment. Please help.

Mathematics

1 answer:

zvonat [6]2 years ago

6 0

SA = LH + LW + WH + 2(1/2LH)
SA = 4*2 + 5*2 + 3*2 + 2*1/2*4*3
SA = 8 + 10 + 6 + 12
SA = 36

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In the figure below, one side of the right triangle is a diameter of the semicircle.

olga55 [171]

Answer:

Option (A)

Step-by-step explanation:

One side of the given triangle is a diameter of the semicircle given.

Measure of the diameter = 10 units

Total area of the semicircle = $\frac{1}{2}\pi (r^{2})$

= $\frac{1}{2}\pi (5)^2$

= 39.27 square units

Area of the right triangle = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(6)(8)$

= 24 square units

Area of the shaded region = Area of the semicircle - Area of the right triangle

= 39.27 - 24

= 15.27 square units

≈ 15 square units

Therefore, option (A) will be the answer.

4 0

3 years ago

The container of orange juice held 53 cups of juice. If a serving of orange juice is g of a cup of orange juice, to the near

svetoff [14.1K]

It is 19 because 53 I know I was guessing Bc Idk Im annoying

8 0

3 years ago

6- the radical of 25 over 4

vladimir2022 [97]

6 - 5/2
which in turn results into 7 halfs
(7/2)

4 0

3 years ago

Ken's landscape gardening business creates odd-shaped lawns that include semicircles. Find the area of this semicircular section

salantis [7]

Answer:

Area of semicircular lawn is 9.82 square meter.

Step-by-step explanation:

Given:

Diameter of the semicircle = 5 m

So we will find the radius.

Radius is half of the diameter.

Radius $r=\frac{5}{2}=2.5\ m$

We need to find the area of the lawn.

Solution:

Now we know that;

Area of semicircle is half times π times square of the radius.

framing in equation form we get;

Area of semicircular lawn = $\frac12\pi r^2=\frac12\times\frac{22}{7}\times 2.5\times 2.5=9.82\ m^2$

Hence Area of semicircular lawn is 9.82 square meter.

7 0

3 years ago

Please help on number 2, multiple choice

goldenfox [79]

F.8 feet is the answer to your problem

6 0

3 years ago

Read 2 more answers