Solve 2x ≤ 30. Round to the nearest ten-thousandth.

Mathematics

1 answer:

trasher [3.6K]3 years ago

7 0

Answer:

Um i think it is B and i'm gonna be honest i'm not as good with math as i am in reading.

Step-by-step explanation:

You might be interested in

What is 130/400 converted into percentage?

d1i1m1o1n [39]

$p\%= \frac{p}{100}$

$\frac{130}{400}= \frac{130\div4}{400\div4}= \frac{32.5}{100}=\boxed{32.5\%}$

7 0

3 years ago

Read 2 more answers

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

3 years ago

HELPPPP (COMLEX NUMBERS AND OPERATIONS

Romashka [77]

Answer:

54 + 39i

Step-by-step explanation:

Given

3i(2 - 5i)(4 + i) ← expand factors using FOIL

= 3i(8 - 18i - 5i² ) → using i² = - 1

= 3i(13 - 18i) ← distribute parenthesis by 3i

= 39i - 54i²

= 54 + 39i

4 0

3 years ago

Find the value of X .

zhenek [66]

The given figure is a Circle, and we know that <u>angle formed by an arc on the center of circle</u> is double the <u>angle formed by it on circumference</u> of the circle,

So,

=》

$x = \frac{180}{2}$