The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250
At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5
So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50
</span>
Answer:
<h2>The answer is 13</h2>
Step-by-step explanation:
x² + y²
x = - 3 , y = - 2
Substitute the values of x and y into the above expression and solve
That's
( - 3)² + (-2)²
= 9 + 4
We have the final answer as
<h3>13</h3>
Hope this helps you
Answer:
<em>X</em><em>=</em><em>5</em><em>3</em><em>°</em><em>+</em><em>4</em><em>5</em><em>°</em><em>=</em><em>9</em><em>8</em><em>°</em>
( BEING EXTERIOR ANGLE OF A TRIANGLE IS EQUAL TO THE SUM OF INTERIOR ANGLES)
Answer:
d = 1/18
Step-by-step explanation: