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BARSIC [14]
3 years ago
13

-18+-6 please help

Mathematics
1 answer:
Verdich [7]3 years ago
6 0

Answer:

-24

Step-by-step explanation:

If you are struggling with this here's a tip!

-18+-6 is what you are trying to solve

The 6 is negative, so get rid of the plus sign -18-6

2 negative numbers are just added like positive numbers

So add 18 and 6, you should get 24

Don't forget about the negative!

-24

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[10 points] A manufacturer wants to design an open box having a square base and a surface area of 108 square inches. What dimens
MissTica

Answer:

  6 inches square by 3 inches high

Step-by-step explanation:

For a given surface area, the volume of an open-top box is maximized when it has the shape of half a cube. If the area were than of the whole cube, it would be 216 in² = 6×36 in².

That is, the bottom is 6 inches square, and the sides are 3 inches high.

_____

Let x and h represent the base edge length and box height, respectively. Then we have ...

  x² +4xh = 108 . . . . box surface area

Solving for height, we get ...

  h = (108 -x²)/(4x) = 27/x -x/4

The volume is the product of base area and height, so is ...

  V = x²h = x²(27/x -x/4) = 27x -x³/4

We want to maximize the volume, so we want to set its derivative to zero.

  dV/dx = 0 = 27 -(3/4)x²

  x² = (4/3)(27) = 36

  x = 6

  h = 108/x² = 3

The box is 6 inches square and 3 inches high.

_____

<em>Comment on maximum volume, minimum area</em>

In the general case of<em> an open-top box</em>, the volume is maximized when the cost of the bottom and the cost of each pair of opposite sides is the same. Here, the "cost" is simply the area, so the area of the bottom is 1/3 the total area, 36 in².

If the box has a <em>closed top</em>, then each pair of opposite sides will have the same cost for a maximum-volume box. If costs are uniform, the box is a cube.

7 0
3 years ago
Which place value first determines which of the numbers 6.399 or 6.400 is the larger number?
kupik [55]

Comparing the numbers, it is found that the tenths value first determines which of the numbers 6.399 or 6.400 is the larger number.

The decimal numbers are 6.399 and 6.400.

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The tenths digit is the <u>first in which there is a difference</u>, hence, it determines which of the numbers 6.399 or 6.400 is the larger number.

A similar problem is given at brainly.com/question/17248958

8 0
2 years ago
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FinnZ [79.3K]

Answer:

V=3888 in³

Step-by-step explanation:

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V=π x 7.5^2 x 22

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5 0
3 years ago
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OverLord2011 [107]

Answer:

3) -11 + 11

Step-by-step explanation:

-11+11=0

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