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melamori03 [73]
3 years ago
7

in a basketball game . Tina made 9 baskets . each dasket was worth either 2 or 3 points how many different numbers could represe

nt the total points that Tina could have made?? answer me​
Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

Tina could make are 10 Possible total points.

They number of possible total points are; 18, 19, 20, 21, 22, 23, 24, 25, 26 and 27.

Step-by-step explanation:

This is a zero-sum sort of deal. If tina makes 9 baskets, they can be all 2 points or all 3 points.

Let's make some number of 2 points "n". Then, the number of 3 points has to be 9 - n. The logic is exactly the same if we considered the number of 3 points made to be "n".

Thus, the maximum of this relationship is when n = 0.

Hence, 9 baskets gives the following possible permutations:

1) 0 number of 2 points and 9 number of 3 points = 27 points

2) 1 number of 2 points and 8 number of 3 points = 26 points

3) 2 number of 2 points and 7 number of 3 points = 25 points

4) 3 number of 2 points and 6 number of 3 points = 24 points

5) 4 number of 2 points and 5 number of 3 points = 23 points

6) 5 number of 2 points and 4 number of 3 points = 22 points

7) 6 number of 2 points and 3 number of 3 points = 21 points

8) 7 number of 2 points and 2 number of 3 points = 20 points

9) 8 number of 2 points and 1 number of 3 points = 19 points

10) 9 number of 2 points and 0 number of 3 points = 18 points

So the number of possible points Tina could make are; 18, 19, 20, 21, 22, 23, 24, 25, 26 and 27.

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