After entering the table values in his calculator, Cory used the LinReg button

Explain to an absent student how to subtract polynomials. Use complete sentences or examples in your explanation.

marishachu [46]

Answer:

Subtracting Polynomials is very similar to adding polynomials. In fact, we will be changing the subtraction problem to an addition problem.

In the Pre-Algebra section of the website, we started out by reviewing integers.

We said, "When you subtract integers, you must add the opposite. We also talked about the Keep - Change- Change Rule. That rule applies to polynomials as well.

Take a look at these examples that show you how to rewrite the problem as an additional problem.

Step-by-step explanation:

5 0

3 years ago

Bag A: Two thirds of the candies are yellow. What portion of the candies is green

dalvyx [7]

Answer: $\frac{1}{3}$ proportion of candies are green.

Solution:

In bag A, $\frac{2}{3}$ candies are yellow.

$\frac{2}{3}$ this proportion shows ratio of favorable over total candies.

Here numerator number is 2.

So, Total number of yellow candies should be 2x

Total number of candies in Bag A would be 3x

Number of green candies in bag A = 3x-2x = x

Now we find the portion of green candies in bag A

$\therefore,$ $\frac{x}{3x}$

$\frac{1}{3}$ portion of candies are green in bag A

7 0

3 years ago

The researchers are concerned that the dollars spent per shopper examined in the study is too different from what has been found

Katarina [22]

Answer:

Step-by-step explanation:

Hello!

To study if the average dollars spend per shopper is different than the expected population average of $84.5 there was a sample of 120 shoppers taken and their spending habit registered.

Then the study variable is:

X: Amount of money spent by a shopper ($)

This population standard deviation is σ= $16

Using the data information I've run a normality test, with p-value: 0.3056 against the test significance level α: 0.05, the decision is to not reject the null hypothesis so there is enough statistical evidence to conclude that the study variable has a normal distribution.

X~N(μ;σ²)

I've also calculated the sample mean and standard deviation:

X[bar]= $81.01

S= $19.62

a.

If the objective is to test that the true mean spending for the population is significantly different than the expected average of 84.5, the parameter of interest is the population mean μ and the hypothesis test will be two-tailed.

H₀: μ = 84.5

H₁: μ ≠ 84.5

α:0.05

The statistic is a standard normal for one sample:

$Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)$

$Z_{H_0}= \frac{81.01-84.5}{\frac{16}{\sqrt{120} } } = -2.389$

p-value two tailed 0.016894

b.

The decision rule using the p-value method is:

If p-value ≤ α ⇒ Reject the null hypothesis.

If p-value > α ⇒ Do not reject the null hypothesis.

Since the p-value is less than the significance level, the decision is to reject the null hypothesis.

c.

Using a level of significance of 5% the null hypothesis was rejected. So there is enough statistical evidence to support the researcher's claim that the true mean spending for the population is significantly different than the expected average of $84.5.

I hope it helps!

3 0

3 years ago

scenario a: get $2,000 deposited into your bank account today, and $50 added each month for a year? make a f(×) function pls

Dennis_Churaev [7]

Mathematics I hate mathematics

7 0

2 years ago

How does this work?????

ankoles [38]

Answer:

x = 4 $\sqrt{5}$