Question

Help please! I’m giving brainliest to however gets this question right.

Answer 1

Answer:

They both have area 4

Step-by-step explanation:

Area of the square:

$base*height = 2 * 2 = 4$

Area of the triangle:

Using the left-side of the triangle as the base, and the height from the left-side to the bottom-right corner:

$\frac{1}{2}base*height$

$\frac{1}{2}4\sqrt2*\sqrt2=4$

We know the length of the diagonal is $\sqrt2$ as we are using a centimetre grid, so we can create an isosceles triangle with side lengths 1 and our unknown length, we can then use Pythagorean Theorem to work out our unknown side length.

$a^2+b^2=c^2$

$1^2+1^2=c^2$

$2=c^2$

$\sqrt2=c$